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2 years ago

WILL MARK AS BRAINLIEST IF CORRECT

Mathematics

1 answer:

Sonbull [250]2 years ago

7 0

Answer:

$x \leqslant 32$

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A triangle has sides with lengths of 43 millimeters, 52 millimeters, and 65 millimeters. Is it a right triangle

Mrrafil [7]

Use pythagora's theorem to test if it is a right triangle

c^2 = a^2 + b^2
65^2 = 52^2 + 43^2
4225 = 2704 + 1849
4225 =/= 4553
therefore it is not a right triangle as it does not comply to pythagora's theorem

7 0

3 years ago

Which decimals are between 10% and 20%? 0.11 0.09 0.13 0 0.19 0.011

Gekata [30.6K]

Answer:

0.19

0.13

0.11

because that is how 19, 13, and 11 percent are represented in decimal form

7 0

2 years ago

Cláudio pode ir de sua casa a escola andando três km para o Norte, 2 para o oeste, um para o sul, quatro para o leste e, finalme

VARVARA [1.3K]

Answer:

b) 2 Km para o leste

Step-by-step explanation:

1. 2 km N

2. 2 km W

3. 1 km S

4. 4 km E

5. 2 km S

Sul e Norte:

(1.) 2 km N + (3.) 1 km S + (5.) 2 km S = 2 km - 1 km - 2 km = 0

Este e Oeste:

(2.) 2 km W + (4.) 4 km E = -2 km + 4 km = 2 km E

Veja imagem abaixo.

7 0

3 years ago

amy is going to put 6 triangular tables together to make one large hexagon shaped table. what will be the area of the hexagon ta

tresset_1 [31]

Answer:

The area of the hexagonal table will be 27 square feet

Step-by-step explanation:

Given:

The height of the triangle = 3 feet

The base of the triangle = 3 feet

To Find:

The area of the hexagonal table = "

Solution:

Step 1: Finding the area of the triangle

The area of the triangle = $\frac{1}{2} \times base \times height$

On substituting the values

The area of the triangle is = $\frac{1}{2} \times 3 \times 3$

The area of the triangle = $\frac{9}{2}$ square feet

Step 2 : Finding the area of the hexagonal table

The area of the hexagonal table is = 6 X area of one triangle

The area of the hexagonal table = $6 \times \frac{9}{2}$

The area of the hexagonal table = $\frac{54}{2}$

The area of the hexagonal table = 27 square feet

3 0

3 years ago

Read 2 more answers

Someone please help with parts a b c and d. I will mark brainlest!!!

maria [59]

Answer:

A. 49 feet

B. 66 feet (round to the nearest foot)

C. 4 seg

Step-by-step explanation:

A. What is the height of the ball after 3 seconds?

For $t=3 seg$

$h(3)=-16(3)^{2} +63(3)+4$

$h(3)=-144+189+4\\h(3)=-144+193\\h(3)=49 feet$

B. What is the maximum height of the ball? round to the nearest foot

$h(t)=-16(t)^{2} +63(t)+4\\h'(t)=-32(t) +63\\$

then

$-32(t)+63=0\\t=\frac{-63}{-32}\\t=1.969seg$

For $t=1.969seg$

$h(1.969)=-16(1.969)^{2}+63(1.969)+4\\h(1.969)= 66.016\\h(1.969)=66 feet$

C. When will the ball hit the ground?

The ball will hit the ground when $h(t)=0$

so, $-16t^{2} +63(t)+4=0$

Using the quadratic equation

$t=4seg$

6 0

3 years ago