2 years ago

WILL MARK AS BRAINLIEST IF CORRECT

1 answer:

7 0

Answer:

$x \leqslant 32$

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finlep [7]

$\begin{array}{llrlll}f(x) = -x +7&~\hspace{10em} &f\left( \boxed{x+4} \right) &=& \boxed{-x+4}+7\\\\&&g(x) &=& -x+11\end{array}$

6 0

2 years ago

Scilla [17]

Answer:

have a good day too

Step-by-step explanation:

6 0

2 years ago

Dmitry [639]

Answer:

Step-by-step explanation:

Hello, dividing by 0 is not defined. so

$\dfrac{2x^2}{6x}$

is defined for x different from 0

This being said, we can simplify by 2x

$\dfrac{2x^2}{6x}=\dfrac{2x*x}{3*2x}=\dfrac{1}{3}x$

and this last expression is defined for any real number x.

Thank you

4 0

3 years ago

klio [65]

Answer:

Step-by-step explanation:

6 divided by.75 if u think I'm wrong check and correct me

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2 years ago

goblinko [34]

i think its 8, not sure but hope it helps.

5 0

3 years ago