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GREYUIT [131]
3 years ago
6

What kind of problem do we need to use “indefinite integral” to solve? Use a real life example to explain.

Mathematics
1 answer:
anastassius [24]3 years ago
4 0

Answer:

Indefinite integration acts as a tool to solve many physical problems.

There are many type of problems that require an indefinite integral to solve.

Basically indefinite integration is required when we deal with quantities that vary spatially or temporally.

As an example consider the following example:

Suppose that we need to calculate the total force on a object placed in a non- uniform field.

As an example let us consider a rod of length L that posses an charge 'q' per meter length and suppose that we place it in a non uniform electric field which is given by

E(x)=\frac{E_{o}}{e^{kx}}

Now in order to find the total force on the rod we cannot use the similar procedure as we can see that the force on the rod varies with the position of the rod.

But if w consider an element 'dx' of the rod at a distance 'x' from the origin the force on this element will be given by

dF=E(x)\times qdx\\\\dF=\frac{qE_{o}}{e^{kx}}dx

Now to find the whole force on the rod we need to sum this quantity over the whole length of the rod requiring integration, as shown

\int dF=\int \frac{qE_{o}}{e^{kx}}dx

Similarly there are numerous problems considering motion of particles that require applications of indefinite integration.

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Answer:

The area of the paralellogram is 24 square units.

Step-by-step explanation:

Geometrically speaking, the area of the parallelogram has an equation equivalent to the area formula for a rectangle, that is:

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Where:

A - Area.

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The base and height of the parallelogram are, respectively:

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3 years ago
Which of the expressions below can be factored using the difference of<br> squares method?
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<em>The second choice is correct. It can be factored as:</em>

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Step-by-step explanation:

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The expression:

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The condition for a binomial to be factored by using this method is that both terms must have an exact square root and they must be subtracted.

The last two choices are not valid because they are not a subtraction but an addition.

The first choice is not valid because none of the terms is a perfect square.

The second choice is correct. It can be factored as:

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