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Goryan [66]
1 year ago
15

T+b = 41 t = 2b+2 Solve for t and b

Mathematics
1 answer:
erastovalidia [21]1 year ago
3 0

Answer: b=13, t=29

Step-by-step explanation:

Substituting the first equation into the second,

2b+2+b=41\\\\3b+2=41\\\\3b=39\\\\b=13\\\\\implies t=2(13)+2=29

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4 0
3 years ago
I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
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6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
3 years ago
What are the zeros of the graphed function y = (x + 3)(x + 5)?
tensa zangetsu [6.8K]
Y=(x+3)(x+5)
0=(x+3)(x+5)
0=x+3
Subtract three on both sides
-3=x
0=x+5
Subtract five on both sides
-5=x
So, -3 and -5 are the zeros of the graphed function.
Hope I helped!
5 0
2 years ago
Read 2 more answers
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