Plot a graph for the following data recorded for an object falling from rest
1 answer:
- The kind of curve obtained is linear.
- The relationship between the variables is direct variation.
- After 4.5 seconds, I expect the velocity to be equal to 140 ft/s.
- The amount of time required for the object to attain a speed of 100 ft/s is 3.2 seconds.
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate, which are the x-axis and y-axis.
In this exercise, you're required to plot a graph for the data (velocity and time) recorded for an object that is falling from rest.
Based on the graph for the data (see attachment), we can logically deduce the following points:
- The kind of curve obtained is linear.
- The relationship between the variables is direct variation.
- After 4.5 seconds, I expect the velocity to be equal to 140 ft/s.
- The amount of time required for the object to attain a speed of 100 ft/s is 3.2 seconds.
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Complete Question:
Plot a graph for the following data recorded for an object falling from rest
a. What kind of a curve did you obtain?
b. What is the relationship between the variables?
c. What do you expect the velocity to be after 4.5 s?
d. How much time is required for the object to attain a speed of 100 ft/s?
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Answer: (a) (b)
Step-by-step explanation:
(a) P( Bill hitting the target) = 0.7 P( Bill not hitting the target) = 0.3
P( George hitting the target) = 0.4 P(George not hitting the target) = 0.6
Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3
= 0.54
Chances that George hit the target is = 0.4 x 0.3 = 0.12
So given that exactly one shot hit the target, probability that it was George's shot = =
.
(b) The numerator in the second part would be the same as of (a) part which is 0.12.
The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.
Given that the target is hit,probability that George hit it = = =