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2 years ago

Resolver por igualación 2x+3y=2 6x+12y=1

Mathematics

1 answer:

tigry1 [53]2 years ago

5 0

Answer:

$x = 3.5$

$y\approx1.666666667$

Step-by-step explanation:

To solve simultaneous equations, at least one of our variables must have the same coefficient. We can easily multiply the first equation by 4 to get 12y on both sides, so let's do that:

$8x + 12y = 8$

No let's subtract the second equation from the first equation to get the third equation:

$2x = 7$

Solve:

$x = 3.5$

Now, we can substitute this value into one of the original equations - let's use the second one:

$21 + 12y = 1$

Solve:

$12y = - 20$

$y = - \frac{ - 20}{12} = \frac{ - 10}{6} = - \frac{5}{3} \approx - 1.66666666667$

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noname [10]

Answer:

Step-by-step explanation:

So lets use the process of elimantion to find the answer.

Firs off, we can tell that this is a greater/less than or equal to inequlaity, since there is a inclosed circle, not a open one. So this leaves the top left answer and bottem right answer.

Now, we can see that the graph is from 0-15. X is at 7.

This means its x+8, because the x would be smaller, or possibly even negatibe on this graph.

My theory that can better support my annwer is if we solve for x:

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We can subtract 8 from both sides:

x=7

And as we can see on the inequality, x is at 7 in the graph.

Hope this makes sense and helps!

6 0

3 years ago

What is the y-intercept: 7x + y = 10

scoray [572]

Answer:

Step-by-step explanation:

7(0)+y=10

y=10

8 0

3 years ago

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y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence

sukhopar [10]

Let

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots$

Differentiating twice gives

$\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots$

$\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n$

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

$\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0$

$\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0$

Then the coefficients in the power series solution are governed by the recurrence relation,

$\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}$

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

$k=0 \implies n=0 \implies a_0 = a_0$

$k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}$

$k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}$

$k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}$

It should be easy enough to see that

$a_{n=2k} = \dfrac{a_0}{(2k)!}$

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

$k = 0 \implies n=1 \implies a_1 = a_1$

$k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}$

$k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}$

$k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}$

so that

$a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}$

So, the overall series solution is

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)$

$\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}$

4 0

3 years ago

how much material was used in the manufacture of 24000 celluloid dice,if each dice has an edge 1/4 inches?

Dovator [93]

The volume of each celluloid die is (.25 x .25 x .25) = 0.015625 cubic inch.

To manufacture 24,000 of them, you need to start with at least

(24,000) x (0.015625) = 375 cubic inches.

I don't know how celluloid is sold, so you should also keep in mind that
375 cubic inches = about 207.8 fluid ounces, or about 6.5 quarts.

I'm sure a bit more than that was used in the manufacture, since
there's always some wasted, spilled, or trimmed off of the edges.

4 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION!!! WHATS THE ANSWER?? I WILL GIVE YOU BRAINLIEST AND A THANKS!!! THANK YOUUU!!! <33

Free_Kalibri [48]

Answer:

A) 113 m²

Step-by-step explanation:

Use the formula for area of a circle.

Area of a circle = πr²

π = pi = 3.14 (rounded)

r = radius

² = the power of 2, or the radius (in this case) multiplied by itself.

Note that the radius is given, and it is 6. Plug in 6 for the radius:

A (circle) = π(6)²

First, solve the power. Multiply 6²:

6² = 6 * 6 = 36

Next, multiply 36 with π (3.14):

36 x 3.14 = 113.04

A) 113 m² is your closest answer.

6 0

2 years ago

Read 2 more answers