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natta225 [31]
2 years ago
12

Resolver por igualación 2x+3y=2 6x+12y=1

Mathematics
1 answer:
tigry1 [53]2 years ago
5 0

Answer:

x = 3.5

y\approx1.666666667

Step-by-step explanation:

To solve simultaneous equations, at least one of our variables must have the same coefficient. We can easily multiply the first equation by 4 to get 12y on both sides, so let's do that:

8x + 12y = 8

No let's subtract the second equation from the first equation to get the third equation:

2x = 7

Solve:

x = 3.5

Now, we can substitute this value into one of the original equations - let's use the second one:

21 + 12y = 1

Solve:

12y =  - 20

y =  - \frac{ - 20}{12}  =  \frac{ - 10}{6}  =   - \frac{5}{3} \approx - 1.66666666667

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6 0
3 years ago
Xue Ying had 143 more sweets than Joanne.After Joanne gave away 22 sweets, Xue Ying had 6 times as many sweets as Joanne. How ma
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Answer:

In the end Joanne had 55 sweets.

Step-by-step explanation:

Let the number of sweets that Xue Ying had be y and let the number of sweets Joanne had be x.

It is given that Xue Ying had 143 more sweets than Joanne. We can write this information as an equation.

               y = x + 143.

It is also given that Joanne gave away 22 of her sweets and after that Xue Ying had 6 times as many more sweets. We can write this as an equation.

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Therefore we can equate the two equations and solve for x.

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Therefore in the end Joanne had 55 sweets.                        

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4 years ago
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