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3 years ago

Solve the compound inequality.

2 answers:

5 0

Thank you for posting your question here, to solve the compound inequality of 5x + 11 ≥ –9 and 10x – 3 ≤ 27 the answer is A which is " x ≥ –4 and x ≤ 3". Below is the solution:

5x + 11 ≥ -9 and 10x - 3 ≤ 27<span>
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
<span>x ≥ -4 and x ≤ 3</span></span>

Molodets [167]3 years ago

3 0

5x + 11 ≥ -9 and 10x - 3 ≤ 27
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
x ≥ -4 and x ≤ 3

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Step-by-step explanation:

Let

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we know that

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The formula to solve a quadratic equation of the form

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in this problem we have

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substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

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therefore

The solution is t=2.62 seconds

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