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Semmy [17]
3 years ago
13

Solve the compound inequality.

Mathematics
2 answers:
Valentin [98]3 years ago
5 0
Thank you for posting your question here, to solve the compound inequality of 5x + 11 ≥ –9 and 10x – 3 ≤ 27 the answer is A which is " x ≥ –4 and x ≤ 3". Below is the solution: 

5x + 11 ≥ -9 and 10x - 3 ≤ 27<span>
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
<span>x ≥ -4 and x ≤ 3</span></span>


Molodets [167]3 years ago
3 0
5x + 11 ≥ -9 and 10x - 3 ≤ 27
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
x ≥ -4 and x ≤ 3
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The solution to given system of equations are (x, y) = (4, 2)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 14 ---------- eqn 1

3x - 4y = 4 --------- eqn 2

We have to solve the given system of equations

We can solve the above system of equations by elimination method

<em><u>Multiply eqn 1 by 3</u></em>

3(2x + 3y = 14)

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<em><u>Multiply eqn 2 by 2</u></em>

2(3x - 4y = 4)

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<em><u>Subtract eqn 4 from eqn 3</u></em>

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( - ) --------------

9y + 8y = 42 - 8

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<h3>y = 2</h3>

<em><u>Substitute y = 2 in eqn 1</u></em>

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<h3>x = 4</h3>

Thus the solution to given system of equations are (x, y) = (4, 2)

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