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3 years ago

Solve the compound inequality.

2 answers:

5 0

Thank you for posting your question here, to solve the compound inequality of 5x + 11 ≥ –9 and 10x – 3 ≤ 27 the answer is A which is " x ≥ –4 and x ≤ 3". Below is the solution:

5x + 11 ≥ -9 and 10x - 3 ≤ 27
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
x ≥ -4 and x ≤ 3

Molodets [167]3 years ago

3 0

5x + 11 ≥ -9 and 10x - 3 ≤ 27
5x ≥ -9 - 11 and 10x ≤ 27 + 3
5x ≥ -20 and 10x ≤ 30
x ≥ -20/5 and x ≤ 30/10
x ≥ -4 and x ≤ 3

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3 years ago

7(8 + y) simplified?

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3 years ago

Carmela mixes 3/4 kilogram of walnuts, 1/2 kilogram of almonds, and 1/4 kilogram of pecans together. She divides the mixed nuts

Evgesh-ka [11]

Amount of walnuts= $\frac{3}{4} kg$

Amount of almonds= $\frac{1}{2} kg$

Amount of pecans= $\frac{1}{4} kg$

Total amount= $\frac{3}{4}+\frac{1}{2}+\frac{1}{4}$

LCM is 4 so sum is = $\frac{3+2+1}{4}=\frac{6}{4}$ = $\frac{3}{2}$

As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:

$\frac{\frac{3}{2}}{\frac{3}{10}}$

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3 years ago

Find two consecutive integers whose sum is 95. Let Statement(s) Equation/Solve Answer(s)

Gre4nikov [31]

47 and 48 are the integers.

Step-by-step explanation:

Let,

x and x+1 be the integers, therefore, according to statement;

$x+(x+1)=95\\x+x+1=95\\2x+1=95\\2x=95-1\\2x=94\\Dividing\ both\ sides\ by\ 2\\\frac{2x}{2}=\frac{94}{2}\\x=47$

2nd Integer = x+1

2nd Integer = 47+1

2nd integer = 48

47 and 48 are the integers.

Keywords: Addition

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3 years ago

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Anuta_ua [19.1K]

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3 years ago

Read 2 more answers