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UNO [17]
3 years ago
10

Emma is a sales clerk at a bicycle shop. She is paid $6.25 per hour for 30 hours work week plus a commission of 8% of sales. In

one week, her sales were $2319.75, what is her gross weekly earning?
Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer: $‭373.08‬

Step-by-step explanation:

First find out what she earned from her normal wages.

She is paid $6.25 per hour for 30 hours in a week. Her weekly pay is therefore:

= 6.25 * 30

= $187.50

She then gets 8% of her sales as commission. Her commission is therfore:

= 8% * 2,319.75

= $‭185.58‬

Her gross pay is therefore:

= Weekly pay + Commission

= 187.50 + 185.58

= $‭373.08‬

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A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

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Answer:

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