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1 year ago

Please solve this question step by step explanation

Mathematics

1 answer:

Leno4ka [110]1 year ago

7 0

The value of ∠B is 60 degrees

<h3>How to solve for B?</h3>

The given parameters are

2∠A = 3∠B = 6∠C

Let the angles in a triangle ABC be ∠A, ∠B and ∠C.

The sum of these angles in the triangle ABC is

∠A + ∠B + ∠C = 180

Multiply the above equation by 2

2 * (∠A + ∠B + ∠C) = 2 * 180

Evaluate the product

2∠A + 2∠B + 2∠C = 360

Recall that 2∠A = 3∠B.

Substitute the above in the equation 2∠A + 2∠B + 2∠C = 360

3∠B + 2∠B + 2∠C = 360

This gives

5∠B + 2∠C = 360

Multiply the above equation by 3

3 * (5∠B + 2∠C) = 3 * 360

Evaluate the product

15∠B + 6∠C = 1080

Recall that 3∠B = 6∠C.

Substitute the above in the equation

So, we have:

15∠B + 3∠B = 1080

Evaluate the like terms

18∠B = 1080

Divide both sides by 18

∠B = 60

Hence, the value of ∠B is 60 degrees

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Solve for x.

Ostrovityanka [42]

Answer:

C. 3, -7

Step-by-step explanation:

x^2 +4x-21 =0

Factor

What 2 numbers multiply to -21 and add to 4

7*-3 = -21

7-3 = 4

(x+7) (x-3) =0

Using the zero product property

x+7 =0 x-3=0

x+7-7=0-7 x-3+3=0+3

x = -7 x=3

3 0

2 years ago

Read 2 more answers

Please help me with #7

Dominik [7]

Step-by-step answer:

This is a regular heptagon, means it has 7 <em>congruent</em> sides and 7 <em>congruent </em>vertex angles.

To work with polygons, there is a very important piece of information that you must know to solve the majority of related problems.

This is:

sum of exterior angles of polygons = 360 degrees.

If you don't remember the 360 degrees, think of the sum of exterior angles of an equilateral triangle, which is 3*(180-60)=3*120=360! It works!

For a regular heptagon, c = 360/7=51.43 degrees approx.

This means that each vertex angle measures

vertex angle = 180-c

So since 2d+the vertex angle = 360, we have

2d+(180-c)=360

solve for d:

2d=360-(180-c)=180+c

d=(180+c)/2=90+c/2=115.71 degrees. (approx.)

8 0

3 years ago

6-10 divide, another onee thank you!!

eduard

Answers:

10.) $\displaystyle \pm{5}$

9.) $\displaystyle 1\frac{1}{2}$

8.) $\displaystyle \pm{1\frac{1}{2}}$

7.) $\displaystyle \pm{1\frac{1}{2}}$

6.) $\displaystyle \pm{\frac{1}{2}}$

Step-by-step explanations:

10.) $\displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}$

9.) $\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}$

8.) $\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

7.) $\displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

6.) $\displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}$