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Colt1911 [192]
3 years ago
5

Twelve pounds of beans are distributed equally into 8 bags to give out at the food bank. How many pounds of beans are in each ba

g
Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0
There are 1.5 beans in 1 bag
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To solve y and x, I am adding a picture
Viktor [21]

Answer:

x =\sqrt 5

y = \sqrt{5

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

\cos(45) = \frac{y}{\sqrt{10}} --- cosine formula i.e. adj/hyp

Solve for y

y = \sqrt{10} * \cos(45)

In radical form, we have:

y = \sqrt{10} * \frac{1}{\sqrt 2}

y = \sqrt{10/2}

y = \sqrt{5

To solve for x, we make use of Pythagoras theorem

x^2 + y^2 = (\sqrt{10})^2

x^2 + y^2 =10

Substitute for y

x^2 + (\sqrt 5)^2 =10

x^2 + 5 =10

Collect like terms

x^2  =10-5

x^2=   5

Solve for x

x =\sqrt 5

4 0
3 years ago
Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan
Lunna [17]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 41  

    Alternate Hypothesis, H_A : \mu > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let \mu = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, H_0 : \mu \leq 41     {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean = 47

            σ = population standard deviation = 35

            n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em>  =  \frac{47-41}{\frac{35}{\sqrt{40} } }

                                      =  1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

                P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

                              = 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

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4 years ago
The perimeter of a rectangle is 42 feet the length is 5 feet longer than the width what are the dimensions
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18.5 x 23.5 is the answer
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a. are for the same time period

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