36-73788+886274=286-773+b=5673

Do any of you know how to easily and properly convert a mixed fraction to a decimal?

arlik [135]

Answer:

Here's a 2 step conversion.

Step-by-step explanation:

1. Convert the fraction to a decimal: Divide the numerator by the denominator

2. Add this decimal number to the whole number part of the mixed number

A mixed number is a whole number plus a fraction. To find the decimal form of a fraction just divide the numerator by the denominator using a calculator or long division. Then add the decimal number to the whole number.

Example: Convert the mixed number 7 1/4 to a decimal

Convert the fraction to a decimal: Divide 1 by 4

1 ÷ 4 = 0.25

Add 0.25 to the whole number 7:

7 + 0.25 = 7.25

8 0

3 years ago

Read 2 more answers

I will mark brainlist if correct !!

dezoksy [38]

Answer:

Yes youre answer is correct

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the product of (a+b) (a-b)

VashaNatasha [74]

Answer:

$a^{2}+b^{2}$

Step-by-step explanation:

(a+b)(a-b)

$a^{2}$ -ab+ab- $b^{2}$

$a^{2} + b^{2}$

5 0

3 years ago

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago

810 songs; 130% increase

horrorfan [7]

To do 130% increase you multiply by 1.3 so you do 810 × 1.3 = 1053

4 0

3 years ago