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Lesechka [4]
1 year ago
13

X + x/3 = 4/9 solve for x!!

Mathematics
1 answer:
Lorico [155]1 year ago
6 0

Answer:

x=1/3

Step-by-step explanation:

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MrRissso [65]
I hope this helps you

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540 is 10 Times as much as 5,400
Sergio039 [100]
Yes, that is true.....
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Can you help me create a polynomial function matching the criteria on the left please and thanks
Olenka [21]

Answer:

f(x) = \dfrac{1}{8}(x + 4)^2(x + 1)(x - 3)

Step-by-step explanation:

From inspection of the graph, we can see that the curve intercepts the x-axis at (-4, 0), (-1, 0) and (3, 0)

Therefore,

x = -4 ⇒ x + 4 = 0

x = -1 ⇒ x + 1 = 0

x = 3 ⇒ x - 3 = 0

Because (-4, 0) touches the x-axis, then (x + 4)² will be a factor

So (x + 4)², (x + 1) and (x - 3) are all factors of the polynomial

\implies f(x) = \dfrac{1}{n}(x + 4)^2(x + 1)(x - 3)

If we multiply the constants, this will give us the y-intercept:

⇒ 4² x 1 x -3 = -48

From inspection of the graph, the y-intercept is -6

So to get from -48 to -6 we need to multiply -48 by 1/8

Therefore, n = 1/8

\implies f(x) = \dfrac{1}{8}(x + 4)^2(x + 1)(x - 3)

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2 years ago
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Question Number 22 You work for a company that manufactures large tarps used for groundcover. An order was placed for a rectangu
Colt1911 [192]

Answer: the area of the finished tarp is 131872 square inches

Step-by-step explanation:

Search strip of tarp is rectangular. The formula for determining the area of a rectangle is expressed as

Area = length × width

An order was placed for a rectangular tarp that will be made up of 8 strips of fabric. Each strip is 26 inches wide and 634 feet long. The area of each strip of tarp is

Area = 26 × 634 = 16484 square inches

Therefore, the area of the finished tarp would be

8 × 16484 = 131872 square inches

4 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
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