The amount of kilograms of each type of original fruit juice weighs; 12 kg of Apple and 6 kg of grape
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The concentrations of apple and grape juice in the two different juice types are given as;
Juice A:
(2/3) apple
(1/3) grape
Juice B:
(1/3) apple
(2/3) grape
Let a be how much juice A is in the mixture;
Let b be how much juice B is in the mix.
Thus;
²/₃a + ¹/₃b = 10 ------(eq 1)
¹/₃a + ²/₃b = 8 ------(eq 2)
Solving both equations simultaneously gives us;
a = 12 and b = 6
Thus, the amount of kilograms of each type of original fruit juice weighs; 12 kg of Apple and 6 kg of grape
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Answer:
1) 29
2) 64
you can use the explanation below to help find the other 6 problems
Step-by-step explanation:
1) 4(5+6) - 15 = 4 * 11 - 15 = 44 - 15 = 29
2) 8(2+4) + 16 = 8 * 6 + 16 = 48 + 16 = 64
Answer:
Since the calculated z=40 falls in the critical region this indicates that the true obesity rate for children in Marion County is different from the national average at the 0.05 significance level. We reject the null hypothesis that population proportion is 0.17.
Step-by-step explanation:
The national average is 17% .The z proportional hypothesis test is used.
1) Let the null and alternate hypothesis be
H0: p =0.17
against the claim
Ha: p ≠ 0.17
Choose the significance level ∝= 0.05
The critical region is z > 1.96 and Z <- 1.96 because it is two tailed test.
Computing
z= p^-p / sqrt [pq/n]
Z= 0.22-0.17/ √0.17*(1- 0.17)/90147
z= 39.965
Since the calculated z=40 falls in the critical region this indicates that the true obesity rate for children in Marion County is different from the national average at the 0.05 significance level. We reject the null hypothesis that population proportion is 0.17.
Answer:
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Step-by-step explanation:
