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Angelina_Jolie [31]
3 years ago
9

A car travels 45 miles per hour on one gallon I gas write an algebraic expression to find the distance the car can travel using

x gallons of gas
Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

y=45x

y represent the distance traveled by the car in x gallons of gas.

Step-by-step explanation:

Given:

A car travels 45 miles  on one gallon of gas.

We need to calculate distance covered by the car in x gallons of gas.

Let y represent the distance traveled by the car in x gallons of gas.

We know that distance traveled by the car directly varies with the amount of gas.

So, we havey ∝ x

Thus y=kx

where k represents the distance traveled by car in 1 gallon of gas.

From the data given we know k=45

So, the expression to find the distance the car can travel using x gallons of gas is written as:

y=45x

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The smaller the angle subtended by a side, the smaller the length of the

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Question 1: The list of sides from shortest to longest are;

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a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

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We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

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a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

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Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

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This is rather simple. Subtract 72 from 81, then put the difference over 72. Then, multiply that by 100.

(81 - 72)/72 * 100

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9/72 * 100

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