Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.
The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.
Answer:
h(x)
h(x)
f(x) g(x) h(x)
Step-by-step explanation:
Edge 2020
~theLocoCoco
Answer:
two is your answer
Step-by-step explanation:
Answer:
a=13
Step-by-step explanation:
-90=-6a-12
-6a=-78
a=13
