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Artyom0805 [142]
2 years ago
6

Solve the system of equations 4x+5y=-1 and -5x-8y=10 by combining the equations.

Mathematics
1 answer:
Flura [38]2 years ago
3 0

The solutions to the given system of equations are x = 6 and y = -5

<h3>Simultaneous linear equations</h3>

From the question, we are to solve the given system of equations

The given system of equation is

4x+5y=-1

-5x-8y=10

Multiply the <u>first equation</u> by 5 and the <u>second equation</u> by 4

5× (4x+5y=-1)

4× (-5x-8y=10)

20x + 25y = -5

-20x - 32y = 40

------------------------

0x + (-7y) = 35

-7y = 35

y = 35/-7

y = -5

Substitute the value of y into the first equation to find x

4x + 5y = -1

4x + 5(-5) = -1

4x -25 = -1

4x = -1 +25

4x = 24

x = 24/4

x = 6

Hence, the solutions to the given system of equations are x = 6 and y = -5

Learn more on Simultaneous linear equation here: brainly.com/question/12647791

#SPJ1

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A website that sells movie tickets can tell what devices are used to access their site and make purchases. The manager of the we
LiRa [457]

Answer:

The best estimate for the proportion of ticket buyers that make purchases using their smart phones is 0.45.

Step-by-step explanation:

We take the estimate from the website, and expand for all buyers, to find the proportion that use their smartphones.

400 users of the website were randomly sampled from the existing database and 180 were found to have used their smart phones.

180/400 = 0.45

The best estimate for the proportion of ticket buyers that make purchases using their smart phones is 0.45.

4 0
3 years ago
A pilot flies on a bearing of 160° for 30 miles. The pilot then executes a quick turn and flies another 15 miles at a bearing of
vivado [14]

Answer: 34.65 miles at an angle of 325.39°

Step-by-step explanation:

Ok, the initial position is (0,0)

Then she flies 30 miles at an angle of 160°, if we count the angle counterclokwise from the x-axis, the new position will be:

p = (30*cos(120°), 30*sin(120°))

Then she travels another 15 miles at an angle of 205°, the new position is:

p = (30*cos(120°) + 15*cos(205°), 30*sin(120°) + 15*sin(205°))

p = (-28.59 , 19.64)

If she now travles X miles at an angle Y, we must have that the final position is the point (0,0)

this means that:

X*cos(Y) = -(-28.59) = 28.59

X*sin(Y) = -19.64

Now, we can find the quotient between those two equations and use that tan(x) = sin(x)/cos(x)

X*(sin(Y))/(X*cos(Y)) = -19.64/28.59

Tg(Y) = -0.69

Y = ATg(-0.69) = -34.61°

If we use only positive angles, this angle is equivalent to:

360° - 34.61° = 325.39°

now lets find the distance:

Xcos(325.39°) = 28.59

X = 28.59/cos(325.39°) = 34.65 miles.

4 0
4 years ago
Zoe's Fish tank holds 27 L of water she uses a 3L container to fill the tank how many times does she have to fill the three litt
Marianna [84]
<h2>Answer:</h2>

Zoe's Fish tank holds 27 L of water, so this is the capacity of the tank. On the other hand, Zoe uses a 3L container in order to fill the tank, so the question is  how many times does she have to fill the three litter container in order to fill the fish tank? Let's solve this as follows:

First time:

She pours 3L

Second time:

She pours another 3L, but she previously poured 3L, so she has poured 6L

Third time:

She pours another 3L, but she previously poured 6L, so she has poured 9L

Fourth time:

She pours another 3L, but she previously poured 9L, so she has poured 12L

Fifth time:

She pours another 3L, but she previously poured 12L, so she has poured 15L

Sixth time:

She pours another 3L, but she previously poured 15L, so she has poured 18L

Seventh time:

She pours another 3L, but she previously poured 18L, so she has poured 21L

Eighth time:

She pours another 3L, but she previously poured 21L, so she has poured 24L

Ninth time:

She pours another 3L, but she previously poured 24L, so she has poured 27L

<em>According to this, she needs to pours the </em><em>3L </em><em>container nine times in order to fill the fish tank. This can also be solved dividing </em><em>27L/3L= 9</em>

4 0
3 years ago
Help me this question
lubasha [3.4K]

Answer:

(a) 218.6 N

(b) 97.14 N

Step-by-step explanation:

When the system is in equilibrium, the net torque on the system is zero.

AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m

Let the centre of gravity of plank is at G.

AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m

(a) Let the reaction at C is R and at D is R'.

R + R' = 29 x 9.8 = 284.2 N ... (1)

Take the torque about C.

29 x 9.8 x CG = R' x GD

29 x 9.8 x 1 = R' x 1.3

R' = 218.6 N

(b) Take the torque about D.

6 x 9.8 x AD = R x CD

6 x 9.8 x (1.5 + 2.3) = R x 2.3

R = 97.14 N

8 0
3 years ago
What is the value of 7​
maw [93]

7 can be written as :-

7 + 0 = 7

7 - 0 = 7

7 × 1 = 7

7 ÷ 1 = 7

7¹ = 7

_____

Hope it helps ⚜

8 0
2 years ago
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