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2 years ago

Which of the following is true when representing a 1:1 binary relationship using the relational model

1 answer:

5 0

When a 1:1 binary relationship is represented by using the relational model: C) the key of either entity is placed in the other as a foreign key.

<h3>What is an entity relationship?</h3>

An entity relationship refers to a data model with the highest level of abstraction and it's designed to avail designers an ability to use a graphical tool to examine structures rather than describe them by using text.

In Computer technology, when a 1:1 binary relationship is represented by using the relational model, the true statement is that the key of either entity is usually placed in the other entity as a foreign key.

Read more on entity relationship here: brainly.com/question/14530873

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Complete Question:

Which of the following is true when representing a 1:1 binary relationship using the relational model?

A) The key of the entity with the highest minimum cardinality must be placed in the other entity as a foreign key.

B) The key of each entity must be placed in the other as a foreign key.

C) The key of either entity is placed in the other as a foreign key.

D) The key of the entity with the most attributes must be placed in the other entity as a foreign key.

E) Both entities must have the same primary key.

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According to C. Wright Mills, what one quality of mind do all great sociologists possess

Semenov [28]

According to C. Wright Mills, one quality of mind do all great sociologists possess is sociological imagination.

<h3>What is sociological imagination?</h3>

Sociological imagination refers to the ability of someone to form an outlook on life through their own personal experiences as they interact with members of their society over time. This outlook they form can change based on newly acquired experiences.

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1 year ago

ENERGÍA ALTERNATIVA

yan [13]

Answer:

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Explanation:

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2 years ago

A bat emits a sound at a frequency of 3. 00 × 104 hz as it approaches a wall. The bat detects beats such that the frequency of t

OLga [1]

Taking into account the Doppler efect, the speed of the bat is closest to 5.02 $\frac{m}{s}$ .

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

$f1=f\frac{v+-vR}{v+-vE}$

Where:

f1, f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 340 m/s
vR, vE: Speed of the receiver and the sender respectively. Its unit of measure in the S.I. is the m/s
±, ∓:

We will use the + sign:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

We will use the sign -:

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

f1= 30,000 Hz + 900 Hz= 30,900 Hz
f= 30,000 Hz
v= 340 m/s
vE=vR= vbat
Receiver approaches the sender

Replacing in the expression is considered the general case of the Doppler effect:

$30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}$

Solving:

$\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}$

$1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}$

1.03×( 340 $\frac{m}{s}$ -vbat)= 340 $\frac{m}{s}$ + vbat

1.03×340 $\frac{m}{s}$ - 1.03×vbat= 340 $\frac{m}{s}$ + vbat

350.2 $\frac{m}{s}$ - 1.03×vbat= 340 $\frac{m}{s}$ + vbat

350.2 $\frac{m}{s}$ - 340 $\frac{m}{s}$ = vbat + 1.03×vbat

10.2 $\frac{m}{s}$ = 2.03×vbat

10.2 $\frac{m}{s}$ ÷ 2.03 = vbat

In summary, the speed of the bat is closest to 5.02 $\frac{m}{s}$ .

Learn more about the Doppler effect:

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2 years ago

3. Which of the following would make it least appropriate to run a dependent/paired samples t-test?

saveliy_v [14]

B sndndnndnndnndnds d. Dndndndkdjdkxkxkd

6 0

3 years ago

Determine the z-score for each team. Show your work. Which team wins the day<br> ?

algol [13]

Any numbers to work with?

8 0

2 years ago