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Sati [7]
2 years ago
8

How many 'words' can be made from the name ESTABROK with no restrictions

Mathematics
1 answer:
Bumek [7]2 years ago
6 0

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

<h3>How to determine the number of ways</h3>

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Learn more about permutation here:

brainly.com/question/4658834

#SPJ1

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Call n, the first of those consecutive terms, then three consecutive terms are:n, n +1, and n +2.

So, the equation will be n + (n +1) + (n +2) = 467

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All of them are valid forms of the equation for the sum of three consecutive integers is 467.

You can solve it now, if you want:

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The solution means that there are not three consecutive numbers whose sume is 467.

You can verifiy that if you take 154 + 155 + 156 = 465

And 155 + 156 + 157 = 468
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