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Wittaler [7]
2 years ago
5

Before the switch is closed in the figure, the potential across the capacitor is 200 V. At some instant after the switch is clos

ed, the instantaneous current is 0.70 A. What is the energy in the capacitor at this instant
SAT
1 answer:
Lerok [7]2 years ago
5 0

The energy in the capacitor at the instant after the switch is closed, based on the potential across the capacitor is 31 mJ

<h3>What is the energy amount in the capacitor?</h3>

Because total energy is constant, this can be found by the formula:

= Initial energy in capacitor - Energy in inductor

The initial energy in the capacitor is:

= 0.5 x 4 x 10⁻⁶ x 200²

= 0.08J

The energy in the inductor is:

= 0.5 x 0.2 x 0.7²

= 0.049

The energy in the capacitor at that instant is:

= 0.08 - 0.049

=0.031 j

= 31 J

Find out more on the energy in the capacitor at brainly.com/question/27960614

#SPJ1

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Answer:

B)x^3

Explanation:

Given,

(x^8)/(x^2)=y^12

We can simplify the following by bringing the (x^2) above the division line which makes the power negative.

(x^8)*(x^-2)=y^12

or,(x^(8-2))=y^12

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The question is, (y^8)/(y^2)=

Simplifying the question,

(y^(8-2))

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Now,from ...(1),

x^6=y^12

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Removing the squares,

x^3=y^6

Thus,we get the answer of the question,

(y^8)/(y^2)=y^6=x^3

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