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3 years ago

8

On a coordinate plane, if you take a point from (2, -5) and move it up 3 units to point "A" what is the distance of point a to c

oordinates (5, 0)?
A. 3
B. Square root of 11
C. Square root of 13
D. 5

2 answers:

likoan [24]3 years ago

5 0

First we need to find the point after the translation of 3 units up.

(2,-5)->(2,-2)

Now we have the point (2,-2) we just need to use the difference formula to find the distance between this point and (5,0)

Distance= $\sqrt{(5-2)^2+(0-(-2))^2}$

Now we need to simplify/solve this expression

= $\sqrt{3^2+2^2}$

= $\sqrt13$

Therefore the answer is C!

tamaranim1 [39]3 years ago

4 0

Answer:

C

Step-by-step explanation:

(2,-5) move up three steps is (2, -2). if you draw it on a paper(and draw lines to connect them), you can see that they form a right triangle. apply a²+b²=c² and you should get 3²+2²=(√13)²

You might be interested in

Percent of decrease of 120 to 52

levacccp [35]

Percent decrease=(decrease)/(original) converted to percent

change=120 to 52
120-52=68
change or decrease=68
original=120
68/120=0.5666666=56.6666%
about 57%

5 0

3 years ago

If f(x) =-2+8 and g(x) = square root of x+9 which statement is true

lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = $\sqrt{x + 9$ , which statement is true?

-6 is in the domain of f(g(x))
-6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

$g(x) = \sqrt{x + 9$

Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute $g(x) = \sqrt{x + 9$

$f(g(x)) = -2\sqrt{x + 9} + 8$

Set the radicand to at least 0

$x + 9 \ge 0$

Subtract 9 from both sides

$x \ge -9$

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true

Read more about domain at:

brainly.com/question/24539784

#SPJ1

3 0

2 years ago

Helppppppppp pleaseeee Someoneeeee pleaseeee I neeed

Stella [2.4K]

Answer:

The minimum value of f(x) is 2

Step-by-step explanation:

To find the minimum value of the function f(x), you should find the value of x which has the minimum value of y, so we will use the differentiation to find it

Differentiate f(x) with respect to x and equate it by 0 to find x, then substitute the value of x in f(x) to find the minimum value of f(x)

∵ f(x) = 2x² - 4x + 4

→ Find f'(x)

∵ f'(x) = 2(2) $x^{2-1}$ - 4(1) $x^{1-1}$ + 0

∴ f'(x) = 4x - 4

→ Equate f'(x) by 0

∵ f'(x) = 0

∴ 4x - 4 = 0

→ Add 4 to both sides

∵ 4x - 4 + 4 = 0 + 4

∴ 4x = 4

→ Divide both sides by 4

∴ x = 1

→ The minimum value is f(1)

∵ f(1) = 2(1)² - 4(1) + 4

∴ f(1) = 2 - 4 + 4

∴ f(1) = 2

∴ The minimum value of f(x) is 2

7 0

3 years ago

Maria compared the slope of the function f(x)=(-6x-21) to the slope of the linear function that fits the values in the table bel

raketka [301]

Answer:

b. both functions have a negative slope

Step-by-step explanation:

The given function is

$f(x)=-6x-21$

This function is of the form $y=mx+b$ , where $m=-6$ is the slope and $b=-21$ is the y-intercept.

We can also determine the slope of the function in the table using any two points, say $(0,7)\:and\:(2,6)$ .

The slope formula is given by,

$m=\frac{y_2-y_1}{x_2-x_1}$ .

If $(x_1,y_1)=(0,7)\:and\:(x_2,y_2)=(2,6)$ , then,

$m=\frac{6-7}{2-0}$

$m=-\frac{1}{2}$ .

We can see that both functions have a negative slope.

The correct answer is B.

8 0

3 years ago

At 107°F, a certain insect chirps at a rate of 92 times per minute, and at 113°F, they chirp 116 times per minute. Write an equa

dsp73

Answer:

The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.

Step-by-step explanation:

A linear equation can be expressed in the form y=m*x + b. In this equation, x and y are coordinates of a point, m is the slope and b is the y coordinate of the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

When there are two points of a line (x1, y1) and (x2, y2), the slope is determined by the quotient between the difference of the ordinate of these two points and the difference of the abscissa of the same points. This is:

$m=\frac{y2-y1}{x2-x1}$

Having a point on the line, you can substitute the values of m, x and y in the equation y = mx + b and thus find b.

In this case:

(x1, y1): (92, 107)
(x2, y2): (116, 113)

So:

$m=\frac{113-107}{116-92}$

m= 0.25

substituting the values of m, x1 and y1 in the equation y = mx + b you have:

107= 0.25*92 + b

107 - 0.25*92= b

84=b

<u><em>The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.</em></u>

3 0

3 years ago