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MArishka [77]
3 years ago
13

Anyone know how to solve this?

Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0
35% of 80 is 28.

80 x 0.35 = 28


I hope this helps.
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Mr. West estimated a mass to be 265g, but upon carefully measuring it, found the actual mass to be 240g. What was the percent er
spayn [35]

Answer:

<h3>The answer is 10.42 %</h3>

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual mass = 240 g

error = 265 - 240 = 25

So we have

p(\%) =  \frac{25}{240}  \times 100  \\  = 10.41666666...

We have the final answer as

<h3>10.42 %</h3>

Hope this helps you

8 0
3 years ago
Can some one solve these?!
ivolga24 [154]
All you need to solve these is a knowledge of the 3 main trigonometrical ratios.
I a right angled triangle where A is a non right angle:-

sin A = opposite / hypotenuse                         (hypotenuse is the sloping side)

cos A = adjacent / hyptenuse       ( the adjacent side is the one the angle 'sits' on)

tan A = opposite / adjacent   (  the opposite side is the one opposite the angle)

So to find the length of segment x in the first problem use

sin 61 = x / 50
 then
x  = 50*sin61  =  43.73 

and to find the length of y:-

cos 61 = y / 50
y = 60 cos 61 =  24.24

The other questions can be solved in a similar way.

7 0
3 years ago
Which statement is true regarding the functions of the graph?
gregori [183]

Answer:

f(- 3) = g(- 3)

Step-by-step explanation:

f(x) and g(x) are equal at the point of intersection.

When x = - 3 , f(- 3) = - 4 and g(- 3) = - 4

Thus

f(- 3) = g(- 3)

4 0
3 years ago
Z^2-16z=-17 what is the solution?​
lys-0071 [83]

Answer:

There are 2 answers,

 z =(16-√188)/2=8-√ 47 = 1.144

 z =(16+√188)/2=8+√ 47 = 14.856

3 0
3 years ago
Read 2 more answers
What is the length of the missing leg?<br> a=
san4es73 [151]

Answer:

a=75

Step-by-step explanation:

85^2-40^2=5625

then the square root of that is 75

6 0
2 years ago
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