complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Answer:
1.no 2.no 3.no 4.no 5.yes 6.yes
7.yes 8.yes 9.no 10.yes 11. yes 12.yes
Step-by-step explanation:
hope that helps
<span>{(3, 7),(3, 6),(5, 4),(4, 7)}not
{(1, 5),(3, 5),(4, 6),(6, 4)}is
{(2, 3),(4, 2),(4, 6),(5, 8)}not
{(0, 4),(3, 2),(4, 2),(6, 5)}is</span>
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Add sides 6
Divide sides by 2
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The correct answer is (( B )) .
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Download Cymath to get the answer
