X^3 - 5x^2 + 3x - 8/x - 3
Steps
First, divide x^3 - 5x^2 + 3x - 8/x - 3: x^3 - 5x^2 + 3x - 8/x - 3 = x^2 + -2x^2 + 3x -8/x - 3
= x^2 + -2x^2 + 3x - 8/x - 3
Second, divide -2x^2 + 3x - 8/x - 3: -2x^2 + 3x - 8/x - 3 = -2x + -3x - 8/x - 3
= x^2 - 2x + -3x - 8/x - 3
Third, divide -3x - 8/x - 3: -3x - 8/x - 3 = -3 + -17/x - 3
= x^2 - 2x - 3 + -17/x - 3
Lastly, simplify
= x^2 - 2x - 3 - 17/x - 3
Answer:
-x/-y
Step-by-step explanation:
Answer: 7+3 =10
Step-by-step explanation: Those were the only two numbers added or subtracted together that I found made 10. I hope this helps :).
Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
Answer:can you give me more detail
Step-by-step explanation: