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Gwar [14]
2 years ago
10

Type the correct answer in each box. Use numerals instead of words.

Mathematics
1 answer:
stira [4]2 years ago
6 0

The system of equations when been placed in a matrix yields

\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]  =\left[\begin{array}{ccc}-175\\25080\end{array}\right]

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the equation:

y = 650x + 175 and;

y = 25080 - 120x

Rearranging the equations gives:

650x - y = -175 and;

120x + y = 25080

Placing the equations in a matrix gives:

\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]  =\left[\begin{array}{ccc}-175\\25080\end{array}\right]

The system of equations when been placed in a matrix yields

\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]  =\left[\begin{array}{ccc}-175\\25080\end{array}\right]

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
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Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

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The two coordinates' x variables are the same, while the y variables change. This means that it is reflected over the x axis. Reflecting over the y axis would cause a change in the x variable, as it would have to move sideways, so this can't be the case since the x variable stays as 4 even after the reflection.

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Cubic bins with closed tops are used to transport melons to the farmers market. The edge length of each bin is 1.5 m. What is th
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We know, Surface area of a Cube = 6a²
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Substitute the value, 
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