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pogonyaev
3 years ago
8

An orange traffic cone has a diameter of 10 in. and a height of 28 in.

Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

733 inches

Step-by-step explanation:

V= 3.14*5^2*28/3

Order of Operations (PEMDAS)

5^2=25

25*3.14= 78.5

78.5*28= 2198

2198/3=732.66

Round to nearest cubic inch

733 inches

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Which of the following is not a type of electromagnetic radiation that telescopes can detect?
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Answer:

B I just got that question it was B

7 0
2 years ago
Jeo is comparing the price of different boxes of cereal. One box has 16 oz. and costs $3.50. Another costs $3.89 for a 24 oz. bo
velikii [3]

Answer:

The difference in cost, in dollars, per ounce between the two boxes of cereal is $0.06.

Step-by-step explanation:

☆Let's solve using proportion.

☆One box:

\frac{16 \: oz.}{3.50 \: dollars}  =  \frac{1 \: oz.}{x}  \\  \\  \frac{3.50}{16}  =  \frac{16x}{16 }  \\  \\ 0.22 = x

☆Another box:

\frac{24 \: oz.}{3.89 \: dollars}   = \frac{1 \: oz.}{x }  \\  \\  \frac{3.89}{24}  =  \frac{24x}{24}  \\ \\ x = 0.16

☆All we need to do is subtract: 0.22 - 0.16 = 0.06

☆The difference in cost, in dollars, per ounce between the two boxes of cereal is $0.06.

7 0
3 years ago
X - 5.1 = -7.6 x is equal to what number
Paul [167]
x-5.1=-7.6 \\\\ x=-7.6+5.1 \\\\ \boxed{x=-2.5}
5 0
3 years ago
Read 2 more answers
there are 90 kids in the band. 20% of the kids own their own instruments, and the rest rent them. how many kids own their own in
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Answer:

18 kids

Step-by-step explanation:

6 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
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