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Olenka [21]
3 years ago
8

What absorbs nutrients that your body needs for food and takes it in the bloodstream

Physics
1 answer:
yulyashka [42]3 years ago
3 0
It's include in the topic of digestive system when when food is travel's from mouth to small intestine there's S intestine get nutrition from the food and sent it to bllod from small vessel's present in it.
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Calculate the speed of a satellite moving in a stable circular orbit about the Earth at a height of 4930 km .
svet-max [94.6K]

The speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

<h3>Speed of the satellite</h3>

v = √GM/r

where;

  • M is mass of Earth
  • G is universal gravitation constant
  • r is distance from center of Earth = Radius of earth + 4930 km

v = √[(6.626 x 10⁻¹¹ x 5.97 x 10²⁴) / ((6371 + 4930) x 10³)]

v = 5,916.36 m/s

Thus, the speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

5 0
2 years ago
two mass Ma=2kg and Mb=5kg on incline are connected together by string as shown below the coefficient of kinetic friction betwee
aniked [119]

Answer:

yourjejejrjrjrjr mother

5 0
3 years ago
Velocity of a car that travled 120 miles in 2 hours
Sophie [7]

60 Miles per hour 60 times 2 is 120

4 0
3 years ago
Read 2 more answers
A car’s momentum is p when it is traveling with a velocity of v. If the velocity of that car doubles, what is the new momentum o
lubasha [3.4K]

Answer:

∆p=(m2v)kg.m/s

Explanation:

∆p=mv where v=2v. hence ∆p=m2v

5 0
3 years ago
Read 2 more answers
A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft
Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

m_1 v_1 = m_2 v_2

m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s

Using the equation to find v_1,

v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475

Using the conservation of energy equation, we have,

KE= \frac{1}{2}m*v^2

KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J

KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J

Total KE= 92077.75+13425530=92708.9J

Now this energy over the cannonball

KE=\frac{1}{2}m*v_2^2

92708.9=\frac{1}{2}15.5v_2^2

V_2 = 109.37m/s

The gain in velocity is 0.37m/s

4 0
3 years ago
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