Physical science challenge me to

How would you describe your appetite over the past couple of weeks? Have your eating habits altered in any way?

wolverine [178]

Answer:

no im in a rehab program so we eat the sam shi every day

Explanation:

brainlest?

5 0

3 years ago

Read 2 more answers

If a net horizontal force of 0.8 N is applied to a toy whose mass is 1.2 kg what acceleration is produced?

julia-pushkina [17]

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{0.8}{1.2} \\ = 0.666666...$

We have the final answer as

Hope this helps you

6 0

3 years ago

A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction

hoa [83]

Given:

Applied stress, $\sigma = 0.45 MPa$

Critical Resolved Stress, $T_{cRss}= 0.242 MPa$

Solution:

a). According to the question, orientation of tensile load is along [1 1 1],

$\sigma = 0.45 MPa$

Now, for resolved shear stress, $\t_{Rss}$ along [1 0 1] within (1 1 T)

let ' $\theta$ ' be the angle between [1 1 1] and [1 0 1], then by coordinate formula:

$cos\theta$ = $\frac{1\times 1 + 1\times 0 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+0^{2}+1^{2}}}}$

$cos\theta$ = $\sqrt{\frac{2}{3}}$

let ' $\phi$ ' be the angle between [1 1 1] and [1 1 1], then by coordinate formula:

$cos\phi = \frac{1\times 1 + 1\times 1 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+1^{2}+1^{2}}}}$

$cos\phi$ = 1

Now, for the resolved components along [1 0 1]

$\t_{Rss}$ = $\sigma cos\theta cos\phi$

$\t_{Rss}$ = $0.45\times 10^{6}\times \sqrt{\frac{2}{3}}\times 1$ = 0.3673 MPa

b). For required tensile stress to produce $T_{cRss}= 0.242 MPa$ :

$\sigma _{1} = \frac{T_{cRss}}{cos\theta cos\phi }$

$\sigma _{1} = \frac{0.242\times 10^{6}}{\sqrt{\frac{2}{3}}\times 1}$

$\sigma _{1} = 0.2964 MPa$

5 0

3 years ago

If you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out. This happens

amm1812

Answer:

True

Explanation:

If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.

<u>Centrifugal force is mathematically related as:</u>

$F=m.r.\omega^2$