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Firdavs [7]
3 years ago
15

Physical science challenge me to​

Physics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

What does this mean i don't get you??

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Can you see an apple in the dark?
abruzzese [7]
No. Because the color of the apple is red.
8 0
3 years ago
A circuit has a source voltage of 50v and a current of 10a. what is the power in watts
Artyom0805 [142]
Power (P)= Voltage (V)* Current (I)
P=50*10=500W

*This is a common answer of mine*
Hope this helps.
8 0
3 years ago
The heavyweight boxing champion of the world punches a sheet of paper in midair, bringing it from rest up to a speed of 26.5 m/s
enyata [817]

corrected question:The heavyweight boxing champion of the world punches a sheet of paper in midair, bringing it from rest up to a speed of 26.5 m/s in 0.044 s . The mass of the paper is 0.003 kg. Part A Find the force of the punch on the paper

Answer:

Force=1.8N

Explanation:

Newtons third law states that in every action there is equal and opposite reaction.

The force of the punch will be the force that moves the paper by a speed of 26.5m/s.

F=ma

F=m\frac{v-u}{t}

m=0.003kg , v=26.5m/s  u=0(the paper is punched from rest) t=0.044s

F=0.003*\frac{26.5-0.044}{0.044}

F=1.8N

4 0
3 years ago
Two identical metal spheres a and b are connected by a plastic rod. both are initially neutral. 1.0×1012 electrons are added to
Ann [662]
The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.

The number of electrons initially given to sphere A is N=1.0 \cdot 10^{12}, and since the charge of 1 electron is e=-1.6 \cdot 10^{-19} C, the net charge left on sphere A after the removal of the rod will be
Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C
8 0
3 years ago
Read 2 more answers
Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
4 years ago
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