Answer:
The x component of the x axis is:
The y component of the y axis is: 
The magnitude is given by: 
The direction is given by: 
See the graphical magnitude and direction below.
Explanation:
The x component of the x axis is:
The y component of the y axis is:
The magnitude is given by:
The direction is given by:
Answer:
While lifting two object the machine needs the different momentum for different mass object.
Explanation:
- Momentum is the quantity of motion contained in an object. Usually it is measured by the product of mass and velocity.
- Momentum of first mass = 2 kg × 2 m/sec = 4 kg m/sec
- Momentum of second mass = 4 kg × 3 m/sec = 12 kg m/sec
- So the machine requires higher mass in motion for second object ( i.e. momentum) than the first one while lifting.
the Doppler effect. (I don't know how to explain it lol)
Answer:
The lightbulb will NOT light.
Explanation:
You put me in a difficult position. I can't help it, but the "sample answer" is by far the best way to explain this, briefly and correctly. There's no other choice but to copy it.
This is a short circuit. The branch without the bulb has almost no resistance, so all the current will flow through that branch instead of flowing through the bulb.
<em>If</em> the lower switch were <u>opened</u>, THEN we would have a series circuit. Current would no longer have any other choice but to flow through the bulb, and the bulb would light.
Answer:
A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes
Explanation:
Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
where,
Vf = Final Velocity of Car = 0 mi/h
Vi = Initial Velocity of Car = 50 mi/h
a = deceleration of car
s = distance covered
Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.
So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:
s = vt
FOR SOBER DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 0.33 s
s = s₁
Therefore,
s₁ = (73.33 ft/s)(0.33 s)
s₁ = 24.2 ft
FOR DRUNK DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 1 s
s = s₂
Therefore,
s₂ = (73.33 ft/s)(1 s)
s₂ = 73.33 ft
Now, the distance traveled by drunk driver's car further than sober driver's car is given by:
ΔS = s₂ - s₁
ΔS = 73.33 ft - 24.2 ft
<u>ΔS = 49.13 ft</u>
