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Debora [2.8K]
4 years ago
10

stion 13 of 20 : Select the best answer for the question. 13. If a certain mass of mercury has a volume of 0.002 m3 at a tempera

ture of 20°C, what will be the volume at 50°C? A. 0.002021624 m3 B. 0.004021624 m3 C. 0.000010812 m3 D. 0.002010812 m3
Physics
1 answer:
Free_Kalibri [48]4 years ago
7 0

Answer : The correct option is, (A) 0.002010812m^3

Solution : Given,

Volume of mercury at temperature 20^oC = 0.002m^3

As we know that the mercury is a liquid substance. So, we have to apply the volume of expansion of the liquid.

Formula used for the volume expansion of liquid :

V_{T}=v_{1}[1+\gamma (T_{2}-T_{1})]

or,

V_{2}=V_{1}[1+\gamma (T_{2}-T_{1})]

where,

V_{T} = volume of liquid at temperature T^oC

V_{1} = volume of liquid at temperature 20^oC

V_{2} = volume of liquid at temperature 50^oC

\gamma = volume expansion coefficient of mercury at 20^oC is 0.00018 per centigrade    (Standard value)

Now put all the given values in the above formula, we get the volume of mercury at 50^oC.

V_{2}=0.002[1+0.00018(50-20)]=0.0020108m^3

Therefore, the volume of mercury at 50^oC is, 0.002010812m^3

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Answer:

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Explanation:

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P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\\dfrac{1000}{5}=\dfrac{F_2}{1}\\\\F_2=200\ N

So, the force needs to be applied on the 1 square meter piston to lift the machine is 200 N. Hence, this is the required solution.

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