A single force acts on a particle situated on the positive x axis. The torque about the origin is in the negative z direction. T
1 answer:
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Answer: Option (b) is the correct answer.
Explanation:
It is given that a positive test charge q is released from rest at a distance r away from a charge of +Q and a distance 2r which is away from a charge of +2Q.
Then test charge to the right immediately after being released.
Therefore, the net force will be as follows.
F =
=
=
F = > 0
Thus, we can conclude that the test charge move to the right immediately after being released.