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kiruha [24]
2 years ago
13

If A and B are independent events and P(A)=0.25 and P(B)=0.333, what is the probability P(ANB)?

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
8 0

The probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333 is <u>0.08325</u>. Hence, <u>option C</u> is the right choice.

For any two events A and B, the probability of event A and B, that is, P(A ∩ B) is given as:-

  1. When the events are dependent, P(A ∩ B) = P(A).P(B|A).
  2. When the events are independent, P(A ∩ B) = P(A).P(B).

In the question, we asked the probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333.

We know that when the events are independent, P(A ∩ B) = P(A).P(B).

Thus, P(A ∩ B) = (0.25)*(0.333),

or, P(A ∩ B) = 0.08325.

Thus, the probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333 is <u>0.08325</u>. Hence, <u>option C</u> is the right choice.

Learn more about the probability of independent events at

brainly.com/question/12783373

#SPJ4

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