Find the equation of a circle with centre at (3, –2) and passing through the point

Mathematics

1 answer:

Llana [10]3 years ago

6 0

Answer:

beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans beans

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I need help on this please

Paha777 [63]

When it's laid out like that. 2 division statements on either side with one unknown variable you just cross multiply really easy

5 x 24 / 6 = 20

Take the number that's on the same position of the x thats 5 then multiply it to the numerator or denominator of the x thats 24 then divide it to its denominator thats 6

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3 years ago

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Scrat [10]

9 because 9⁴ gives you that result, you can try on a calculator ;)

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3 years ago

Standard form of the equation that goes through (3, -1) with a slope of -1, please!

11111nata11111 [884]

Answer:

x+y=2

Step-by-step explanation: