Henge

Type a digit that makes this statement true. HELPPPP MEEEEE PLZZZZZ!!!

Usimov [2.4K]

Answer:

2

Step-by-step explanation:

Ok so basically you want a number that is evenly divisible by 4. Or in other words 4 x ? = 691,61#

The easiest thing to do is start with a zero there and divide it by 4 to see what you get.

691,610 / 4 = 172,902.5

Since this is not evenly divisible by 4 let's round it up to the next whole number and multiply by 4

4 x 172,903 = 691,612

So the digit you can put on the end of the number is 2

6 0

2 years ago

Read 2 more answers

Two parallel lines are cut by a transversal. Which statements are true for all such cases? Select three that apply.

Rudiy27

Answer:

Step-by-step explanation:

Each pair of vertically opposite angles are equal. If you mean vertical angles as in 90 degrees, you should qualify the question

Each pair of alternate interior angles is congruent (think it should be are congruent).

Each pair of corresponding angles is congruent

8 0

2 years ago

Nathan usually drinks 37 ounces of water per day. He read that he should drink 62 ounces of water per day. If he starts drinking

Bad White [126]

Answer:

68%

Step-by-step explanation:

The increase is (62 - 37), or 25, ounces. Comparing this to the original quantity (37 oz), we divide 25 oz. by 37 oz., obtaining 0.676 (a ratio). Multiplying this ratio by 100%, we get 68% (to the nearest percent).

5 0

3 years ago

I only need #16 this Test/homework is hard. Help

Amiraneli [1.4K]

Answer:

d

Step-by-step explanation:

8 0

2 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago