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3 years ago

The radius of circle L is 16 cm.

Mathematics

1 answer:

timurjin [86]3 years ago

6 0

The anwser is for the question tht u are looking for is no other then the first anwser A!!!

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A 2-column table with 5 rows titled Length Conversion. Column 1 is labeled Inches, x with entries 2, 4, 7, 10, 13. Column 2 is l

suter [353]

Answer:

a) en cuántas filas la suma es igual?

2+7+2+0+2=13

0+1+6+1+0=8

2+0+2+8+1=13

es igual en dos filas la primera y la última

b)en cuántas columnas la suma es igual?

2+0+2=4

7+1+0=8

2+6+2=8

0+1+8=9

2+0+1=3

es igual en dos columnas la segunda y la tercera

listo :)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2

guapka [62]

Step-by-step explanation:

$\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)$

Use the identity

$\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}$

on the left side.

$\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

$\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

Now use the identity

$\sin \theta = \cos(\frac{\pi}{2} - \theta)$

on the left side.

$\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

$\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)$

4 0

2 years ago

4st^2-s^2 were s=5 and t=7

barxatty [35]

➣ Assignment: $\bold{Solve \ Equation: \ \left(4\left(5\cdot \:7^2\right)\right)-5^2}$

↔↔↔↔↔↔↔↔

➣ Answer: $\boxed{\bold{955}}$

↔↔↔↔↔↔↔↔

Explanation: ↓↓↓↓↓

↔↔↔↔↔↔↔↔

➤ [ Step One ] Follow PEMDAS Order Of Operations

$\bold{4\left(5\cdot \:7^2\right): \ 980}$

➤ [ Step Two ] Rewrite Equation

$\bold{4\left(5\cdot \:7^2\right)}$

➤ [ Step Three ] Calculate Within Parenthesis

$\bold{4\left(5\cdot \:7^2\right): \ 245}$

➤ [ Step Four ] Rewrite Equation

$\bold{4\cdot \:245}$

➤ [ Step Five ] Multiply

$\bold{4\cdot \:245: \ 980}$

➤ [ Step Six ] Rewrite Equation

$\bold{980-5^2}$

➤ [ Step Seven ] Calculate Exponents

$\bold{5^2: \ 25}$

➤ [ Step Eight ] Rewrite Equation

$\bold{980-25}$

➤ [ Step Nine ] Solve

$\bold{955}$

↔↔↔↔↔↔↔↔

$\bold{\rightarrow Mordancy \leftarrow}$

4 0

3 years ago

10483 people attended a rock festival. if there were 811 more boys than girls, and 2481 fewer adults over 50 years of age than t

Bond [772]

Answer: 4051 girls, 4862 boys and 1570 adults over 50 years of age group attended the festival.

Step-by-step explanation:

Let x denotes the number of girls.

Then, the number of boys = x+811

The number of adults over 50 years of age = x-2481

Now, by considering the given scenario :-

$x+x+811+x-2481=10483\\\\\Rightarrow\ 3x-1670=10483\\\\\Rightarrow\ 3x=10483+1670\\\\\Rightarrow\ 3x=12153\\\\\Rightarrow\ x=\dfrac{12153}{3}=4051$

Thus, the number of girls attended the festival = 4051,

Then number of boys = 4051+811=4862

Number of adults = 4051-2481=1570

7 0

3 years ago

Which statement best explains the relationship between numbers divisible by 5 and 10

densk [106]

0 because you can divide them ie 0 is divisible with 5 and 10

4 0

3 years ago