Answer:
f(t) = 66·0.995^t
Step-by-step explanation:
You can try t=0 and t=1 in each of the formulas to see which one gives values of 66 and 0.5% less than 66, or 65.67.
The first function has an initial value of 0.5, so is not correct.
The second function gives f(1) = 99, so is not correct.
The third function gives f(1) = 65.67, so is correct.
The fourth function gives f(1) = 66.33, so is not correct.
_____
You can realize that the multiplier will be 0.5% less than 100%, so will be 99.5% = 0.995. This number shows up only in the third selection.
Answer:
$11.23
Step-by-step explanation:
To find the unit price divide the price by the product. For example, 12 ounces of juice costs $2.45. You divide $2.45 by 12 ounces. The unit price would be $0.20.
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Answer: True, angles that are congruent are equaled to each other
Answer:
A. 30.144
Step-by-step explanation:
This is a Chi-Squared test
Given:
- The significance level is 5%, so
To use the Chi-Square distribution table, you need to know two values:
- Degrees of freedom = (n - 1)
- Significance level
Degrees of Freedom = n - 1 = 20 - 1 = 19
The significance level is 5%, so
This is a one-tailed test since so Upper tail area = 0.05
Reading from the table (attached), the critical value is: 30.144
(This means that we reject 
if the test statistic is greater than 30.144)
Answer: p-value of the test = 0.167
Step-by-step explanation:
Given that,
sample size n = 400
sample success X = 80
confidence = 95%
significance level = 1 - (95/100) = 0.05
This is the left tailed test .
The null and alternative hypothesis is
H₀ : p = 0.22
Hₐ : p < 0.22
P = x/n = 80/400 = 0.2
Standard deviation of proportion α = √{ (p ( 1 - p ) / n }
α = √ { ( 0.22 ( 1 - 0.22 ) / 400 }
α = √ { 0.1716 / 400 }
α = √0.000429
α = 0.0207
Test statistic
z = (p - p₀) / α
z = ( 0.2 - 0.22 ) / 0.0207
z = - 0.02 / 0.0207
z = - 0.9661
fail to reject null hypothesis.
P-value Approach
P-value = 0.167
As P-value >= 0.05, fail to reject null hypothesis.
Since test is left tailed so p-value of the test is 0.167. Since p-value is greater than 0.05 so we fail to reject the null hypothesis.
