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Mnenie [13.5K]
3 years ago
10

Simplify 3^2 x 3^3 A. 3 B. 3^6 C. 3^5 D. 3^8

Mathematics
1 answer:
Maslowich3 years ago
5 0
When you are multiplying and have like bases, then you add the exponents. 
2+3=5
3^5
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Please help me
yKpoI14uk [10]

9514 1404 393

Answer:

  A)  5x+12 = -12x-12

  D)  5x+12 = -5x-12

Step-by-step explanation:

If you subtract the right side expression from both sides, you will get an equation with something equal to zero. If the 'something' has a variable in it, there is exactly one solution.

A: (5x+12) -(-12x-12) = 17x+24 = 0 . . . one solution

B: (5x+12) -(5x-5) = 17 = 0 . . . . no solutions

C: (5x+12)-(5x+12) = 0 = 0 . . . . infinite solutions

D: (5x+12) -(-5x-12) = 10x +24 = 0 . . . one solution

6 0
2 years ago
What’s the equation.?
Stella [2.4K]

Answer:

See below

Step-by-step explanation:

You know that he spent 1/3 of his earnings, and then 1/4. After this, he has $28.90. You can write the equation like this:

1/4(x * 1/3) = $28.90.

If you need to solve it:

1/4 * 1/3x = 28.90

1/12x = 28.90

x = 346.80

8 0
3 years ago
The equation of line KL is y=-1/2x-6. The equation line WX is 7x-14y=-42. Rewrite the equation of line WX in slope-intercept for
Alexus [3.1K]
Hope you are able to understand the solution. :-D

8 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
Six plus what equals -2
Rudiy27

Answer: -8

Step-by-step explanation:

6+ -8 = -2

7 0
3 years ago
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