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ozzi
2 years ago
12

You have 1 blue suit, 2 black suits, and 1 brown suit, You also have 2 blue ties, 3 red ties, and 3 pink ties. What is the proba

bility that you pick a striped shirt AND a blue suit AND a pink tie
Mathematics
1 answer:
tia_tia [17]2 years ago
8 0

The probability that you pick a striped shirt AND a blue suit  is 1/4 AND a pink tie is 3/8.

According to the statement

Number of blue suit = 1

Number of black suit = 2

Number of brown suit = 1

Number of blue ties = 2

Number of red ties = 3

Number of pink ties = 3

Now we find the probability by its formula

Probability that picked suit is blue = blue suits/ total number of suits

Probability = 1/4

Now,

Probability that picked tie is pink = Pink tie / total number of ties

Probability = 3/8

So, The probability that you pick a striped shirt AND a blue suit  is 1/4 AND a pink tie is 3/8.

Learn more about PROBABILITY here brainly.com/question/7965468

#SPJ4

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3 years ago
Read 2 more answers
Use the formula to evaluate the series 1/4 + 1/9 + 1/27 + 1/81.
Dmitriy789 [7]
Is the first term supposed to be 1/4, or did you actually mean 1/3?

I'll assume the latter. Write

S=\dfrac13+\dfrac19+\dfrac1{27}+\dfrac1{81}
S=\dfrac13+\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}
\dfrac13S=\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}+\dfrac1{3^5}
\implies S-\dfrac13S=\dfrac13-\dfrac1{3^5}
\dfrac23S=\dfrac13\left(1-\dfrac1{3^4}\right)
S=\dfrac12\left(1-\dfrac1{81}\right)
S=\dfrac{40}{81}
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28
Nataliya [291]
Assuming you mean

5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t

This ODE is linear in y, and you can already contract the left hand side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t

Integrating both sides with respect to t yields

5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt
5y\sin t=\dfrac13\sin^3t+C
y=\dfrac1{15}\sin^2t+C\csc t

Given that y\left(\dfrac\pi2\right)=9, we have

9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2
9=\dfrac1{15}+C
C=\dfrac{134}{15}

so that the particular solution over the interval is

y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t
6 0
3 years ago
Lexi Susie and Ryan are playing on online word game Royals score 100034 points Lexi scores 9348 fewer points t
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7 0
4 years ago
1. What is the constant of proportionality?<br><br> 2. What is the equation?
expeople1 [14]

Answer:

y = 1/3a

Step-by-step explanation:

y = ka

1 = 3k

k = 1/3

Confirm constant: (4-1)/(12-3) = 3/9 = 1/3

1 = 3(1/3) + b

1 = 1 + b

b = 0

y = 1/3x or 1/3a

7 0
3 years ago
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