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charle [14.2K]
3 years ago
11

Use the graph at the top to figure out the question. If someone could help they would be great! And brainliest.

Mathematics
1 answer:
mariarad [96]3 years ago
8 0

Answer: A

Step-by-step explanation:

Each gallon costs 3 dollars.

8(gallons) times $3(for each gallon) = 24(dollars).

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The line that is perpendicular to y=-x and passes through the point (2,4) is y=x+ ___?
iris [78.8K]

Answer:

B. 2

Step-by-step explanation:

1) all the perpendicular lines are: y=x+C, where C - number;

2) in order to calculate C: to substitute (2;4) into the equation y=x+C:

4=2+C; ⇒ C=2;

3) finally, the required equation is: y=x+2.

The answer is B. 2.

3 0
2 years ago
19. Solve the equation 3cos x = 8tan x, between Oº and 360°
Alex

3\cos x=5\tan x\\\\3\cos x=5\cdot\dfrac{\sin x}{\cos x}\\\\3\cos^2 x=5\sin x\\\\3(1-\sin^2x)=5\sin x\\\\-3\sin^2x-5\sin x+3=0\\\\t=\sin x\qquad\qqaud t\in\\\\-3t^2-5t+3=0\\\\3t^2+5t-3=0\quad\implies\quad a=3\,,\ b=5\,,\ c=-3\\\\t=\dfrac{-5\pm\sqrt{5^2-4\cdot3\cdot(-3)}}{2\cdot3}=\dfrac{-5\pm\sqrt{25+36}}{6}=\dfrac{-5\pm\sqrt{61}}{6}\\\\t_1=\dfrac{-5+\sqrt{61}}{6}\approx0.4684\ ,\qquad t_2=\dfrac{-5-\sqrt{61}}{6}\approx-2.136\notin

\sin x=0.4684\quad\wedge\quad x\in(0^o,\ 360^o)\\\\x\approx28^o\qquad\qquad\vee\qquad x\approx152^o\\\\\\\sin x=0.4684\quad\wedge\quad x\in(0,\ 2\pi)\\\\x\approx0.4887\qquad\qquad\vee\qquad x\approx2.6529

6 0
2 years ago
Find the sum of the first 50 terms of the sequence below.<br> An = 3n + 2
andrezito [222]
An+1= 3n+3 +2
An+1 - An = <span>3n+5 -3n-2=3
An is aa arithmetic sequence
its sum is given by:
A0 +A1 +A2 + . . . + An = N(Ao + An) /2
where N = n-0=n
</span><span>S50= A0 +A1 +A2 + . . . + A50 = 50(Ao + A50) /2
</span>
S50 = 50(Ao + A50) /2
Ao=2, A50=150+2=152
S50= <span>50(Ao + A50) /2
</span>
finally
<span>S50=25*154=3850</span>

4 0
3 years ago
Read 2 more answers
How do I do these 4 geometry please help
julsineya [31]

Answer:

7) Similar; 8) not similar; 9) ⅔; 10) ⅘

Step-by-step explanation:

Two polygons are similar if

  • their corresponding angles are congruent and
  • the ratios of their corresponding sides are equal

7) Trapezoids

Corresponding angles are congruent.

\dfrac{30}{12} = \dfrac{15.5}{6.2} = \dfrac{40 }{16}} = \dfrac{5}{2}

Corresponding sides are in the same ratio, so the trapezoids are similar.

8) Rectangles

Corresponding angles are congruent.

\text{Ratio of bases} =\dfrac{42}{35} = \dfrac{7}{5}\\\\\text{Ratio of sides} =\dfrac{24}{25}

The ratios are different, so the rectangles are not similar.

In similar polygons, the ratio of the lengths of their corresponding sides (the scale factor) is the same.

9. Quadrilaterals

\text{Scale factor} = \dfrac{10}{15} = \mathbf{\dfrac{2}{3}}

10. Trapezoids

\text{Scale factor} = \dfrac{16}{20} = \mathbf{\dfrac{4}{5}}

8 0
3 years ago
Plz help hurry thx ​
Hatshy [7]

Answer:

2nd one

Step-by-step explanation:

..... if u want me to explain it just comment

3 0
2 years ago
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