One thing everyone always forgets is we don't usually see the <em>entire</em> graph. Once out of the frame, these functions can do anything they want.
From what we can see, only the bottom right one is always decreasing.
Answer: bottom right
By the way, the top right graph (a vertical line) isn't a function.
So 1st make it equal to zero
x^2+4x-12
(x+6)(x-2)
so
x=-6 or 2 is the correct answer
B because The measure of center of distribution would have to be in be
Answer:
The value of a = - 1 , And b =
Step-by-step explanation:
Given as :
Function f(x) = 
And f(f(1)) = 0 And f(2) = - 3
Now For , x = 2 , y = - 3
I.e f(2) = 
or, - 3 =
I.e 2 + a = - 6 - 3b
Or, a + 3b = - 8 ....... 1
Again f(f(1)) = 0
So,
= 0
Or, 1 + a = 0
∴ a = - 1
So , put htis value of a i n eq 1 , we get value of b
So , - 1 + 3b = - 8
Or, 3b = - 7
∴ b =
Hence The value of a = - 1 , And b =
Answer
Answer:
D
Step-by-step explanation:
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