Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
The answer should be 1,656 for #1.#2 is 1,134 flakes are left. Temmie is mad at frisk and chara for taking her flakes....GRRRRR:((((:((:(:(:(::(:(:(:(:(:(:(:((::(:(:(:(:(
2 consecutive numbers....x and x + 1
x(x + 1) = 182
x^2 + x = 182
x^2 + x - 182 = 0
(x - 13)(x + 14) = 0
x - 13 = 0
x = 13
x + 14 = 0
x = -14....not this one because it is negative
x + 1 = 13 + 1 = 14
ur 2 numbers are : 13 and 14
Answer:
120
Step-by-step explanation:
For this, all we have to do is multiply 750 by 16%. We know, from percent to decimal conversion, that 16% is 0.16 (divide the percent by 100 to convert to a decimal). From there, if we multiply 750 by 0.16, we get our answer to be 120
The answer to this question is 10.6
