The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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Let's start with the blue states. Out of 50 states, 28 of them were blue.
Therefore, the fraction would be 28/50. Let's reduce it.
28/50=14/25 --> these are the lowest terms for this fraction
Use a calculator to find the decimal solution --> 14/25= .56
Now, let's do the red states. Out of the 50 states, 22 of them were blue.
22/50=11/25 --> lowest terms
Use a calculator --> 11/25= .43
Answer:
14.52
Step-by-step explanation:
13.57 + 13.57 x 7% = 13.57 x (1+7/100) =13.57 x 107/100 = 14.52
Hi!
So for this problem, we're given the y-coordinate and we can plug that in for y in the equation. So let's do that
-1 = -3/5x - 7
6 = -3/5x
30 = -3x
-10 = x
The missing coordinate would be x, assuming that the equation was y = (-3/5)x - 7
Answer:
24
Step-by-step explanation:
