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ch4aika [34]
2 years ago
13

The length of a rectangle is 8 inches more than the width. the perimeter is 44 inches. find the length and width of the rectangl

e
Mathematics
1 answer:
vazorg [7]2 years ago
8 0

Answer: Width is 7 inches, length is 15 inches.

Step-by-step explanation:

Let the width be w. Then, the length is w+8.

2(w+w+8)=44\\\\w+w+8=22\\\\2w+8=22\\\\2w=14\\\\w=7\\\\\implies l=15

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Maksim231197 [3]

Hey there! I'm happy to help!

If you raise a fraction to an exponent, you apply that exponent to the numerator and the denominator. This would give us \frac{y^4}{x^4}.

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3 years ago
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What is the approximate area of a circular pond that has a radius of 35 meters?​
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A=r^ 2 * pi=35^ 2 *3.14=3846.5m
7 0
3 years ago
NEED THIS DONE ASAP<br><br><br> If P(x) = -2(1 - x)2 +5, what is the value of<br> P(-3)?
marusya05 [52]

Answer:

P(-3) = -1

Step-by-step explanation:

So just substitute the value of x in the equation:

Value of x is (-3)

So:

P(x) = -2(1 - x)2 +5

P(-3) = -2(1-(-3)) 2 + 5

P(-3) = -2(4) 2 + 5

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4 0
3 years ago
!!!!NEED HELP ASAP!!!! NO LINKS OR REPORT
Mariana [72]

Answer:

y = 3x - 5

Step-by-step explanation:

So first take any two points from the graph.

(0, -5), (2, 1)

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y = mx + b

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3 0
2 years ago
The number of showtimes for one movie over several days is shown. What is the mean absolute deviation (MAD)? 9, 6, 8, 9, 7, 4, 3
velikii [3]

Given:

The data set is:

9, 6, 8, 9, 7, 4, 3, 5, 2, 4

To find:

The mean absolute deviation (MAD) of the given data.

Solution:

We have,

9, 6, 8, 9, 7, 4, 3, 5, 2, 4

The mean of the given data set is:

\overline{x}=\dfrac{1}{n}\sum x_i

\overline{x}=\dfrac{1}{10}(9+6+8+9+7+4+3+5+2+4)

\overline{x}=\dfrac{1}{10}(57)

\overline{x}=5.7

So, the mean of the given data set is 5.7.

The mean absolute deviation (MAD) is:

MAD=\dfrac{1}{n}\sum |x-\overline{x}|

The mean absolute deviation (MAD) of the given data is:

MAD=\dfrac{1}{10}(3.3+0.3+2.3+3.3+1.3+1.7+2.7+0.7+3.7+1.7)

MAD=\dfrac{1}{10}(21)

MAD=2.1

Therefore, the mean absolute deviation (MAD) of the given data set is 2.1.

5 0
3 years ago
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