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2 years ago

Which of the following correlation coefficients would represent the strongest correlation? -0.9 -0.16 0.04 .78

Mathematics

1 answer:

kolezko [41]2 years ago

8 0

Answer:

0.4 would represent the strongest correlation.

Step-by-step explanation:

Generally, a value of r greater than 0.7 is considered a strong correlation. Anything between 0.5 and 0.7 is a moderate correlation, and anything less than 0.4 is considered a weak or no correlation

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Which one of these is the correct answer?

sukhopar [10]

Answer:

the top answer.............

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2 years ago

Given h(x) = -7x + 1, find x if h(x) = 50

vazorg [7]

Answer:

-7

Step-by-step explanation:

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3 years ago

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Write an equation in point-slope form and slope-intercept form

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Answer:

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Step-by-step explanation:

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2 years ago

Which two complex numbers when added together and written in standard form equal 10-3i?

dedylja [7]

Answer:

A -3 − 4i C 13 + i

Step-by-step explanation:

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4 0

3 years ago

. A shipyard makes a container ship that can withstand the total amount of weight W, which is normally distributed with mean of

Debora [2.8K]

Answer:

the maximum number of containers that the ship can load is 170

Step-by-step explanation:

Given the data in the question;

W ~ N( 600, 60 )

S ~ N( 4n, 0.4√n )

p( W > S ) = 0.90

⇒ P( W - S > 0) = 0.9 ------ let this be equation 1

now, since W and S are independent

Mean( W - S ) = Mean( W ) - Mean( S 0 = 600 - 4n

and

SD( W - S ) = √( var(W) + var(S) ) = √( 60² + 0.4²n)

hence;

W - S ~ N( 600 - 4n, √( 60² + 0.4²n) )

now, from equation one, P( W - S > 0) = 0.9

$P( \frac{(W-S)-Mean(W-S)}{SD(W-S)} > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = 0.90$

$P( z > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = 0.90$

from z- table

$P( z > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = P( z >-1.282)$

$\frac{4n - 600}{\sqrt{60^2 + 0.4^2n} } = -1.282$ ------------------ let this be equation 2

now, we square both sides of equation 2

$\frac{(4n - 600)^2}{60^2 + 0.4^2n} } = (-1.282)^2$

$\frac{(4n - 600)(4n-600)}{3600 + 0.16n} } = 1.643524$

we cross multiply

16n² + 360000 - 4800n = 1.643524( 3600 + 0.16n )

16n² + 360000 - 4800n = 5916.6864 + 0.26296384n

16n² + 360000 - 5916.6864 - 4800n - 0.26296384n = 0

16n² + 354083.3136 - 4800.26296384n = 0

16n² - 4800.26296384n + 354083.3136 = 0

solving the quadratic equation, we know that;

x = -b±√( b² - 4ac ) / 2a

so we substitute

x = [-(-4800.26296384) ±√( (-4800.26296384)² - (4 × 16 × 354083.3136)] / [2×16]

x = [ 4800.26296384 ±√( 23042524.522 - 22661332.0704 ] / 32

x = [ 4800.26296384 ±√(381192.4516) ] / 32

x = [ 4800.26296384 ± 617.4078 ] / 32

Hence;

x = [ 4800.26296384 - 617.4078 ] / 32 or [ 4800.26296384 + 617.4078 ] / 32

x = 131 or 170

Therefore, the maximum number of containers that the ship can load is 170

5 0

3 years ago