Answer:
Slope = 0
Explanation:
m= (−7) − (−7) / (−13) − (−1) = 0
(x1,y1)=(−1,−7) and (x2,y2)=(−13,−7). Since y1=y2 therefore this line is parallel to x-axis. Hence slope is zero.
Answer:
x = 3
y = 4
Step-by-step explanation:
if we look at the pixels in the table we can see with our eyes that the dots are plotted on these graph positions
x: 3
y: 4
Let us assume that the number of hours of regular work day to be "X". Since the total number of hours worked is 11, the additional hours that the worker put in would be "11-X"
Now, we form the equation to solve for X.
The wage for a regular hours is $9 for X hours worked which would make the pay = 9X
The wage for additional "11-X" hours is $13.50 which would make the pay = (11-X)*13.50
The total the worker was paid for 11 hours is 114.75, so the equation would be
9X +(11-X)*13.50 = 114.75
9X +148.5-13.50X = 11.75
4.5X = 33.75
X = 7.5
So, the length of a regular workday is 7.5 hours
Answer: The required matrix is
![A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%264%260%5C%5C0%266%268%5C%5C0%260%266%5Cend%7Barray%7D%5Cright%5D%20.)
Step-by-step explanation: The given linear transformation is
T(f(t)) = 4f'(t) + 6f(t).
We are to find the matrix A of T from P² to P² with respect to the standard basis P² = {1, t, t²}.
We have

Therefore, the matrix A is given by
![A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%264%260%5C%5C0%266%268%5C%5C0%260%266%5Cend%7Barray%7D%5Cright%5D%20.)
Thus, the required matrix is
![A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%264%260%5C%5C0%266%268%5C%5C0%260%266%5Cend%7Barray%7D%5Cright%5D%20.)
Answer: 18
Step-by-step explanation:
subtract 5 - 7; since that's not possible make the 3 into a 2 and add a 1 in front of the 5; now do 15-7 = 8. 2-1 =1 ----> 18