Answer:
import java.util.Scanner;
// Needed for the Scanner class This program calculates the user's gross pay.
public class Pay {
public static void main(String[] args) {
// Create a Scanner object to read from the keyboard.
Scanner keyboard = new Scanner(System.in);
// Identifier declarations
double hours;
// Number of hours worked
double rate;
// Hourly pay rate
double pay;
// Gross pay
// Display prompts and get input.
System.out.print("How many hours did you work? ");
hours = keyboard.nextDouble();
System.out.print("How much are you paid per hour? ");
rate = keyboard.nextDouble();
// Perform the calculations.
if (hours <= 40) {
pay = hours * rate;
}
else
{
pay = (hours - 40) - (1.5 * rate) + 40 - rate;
}
// Display results.
System.out.println("You earned $" + pay);
}
}
Explanation:
Answer:
B. Fuser unit
Explanation:
Based on the scenario that is being described it can be said that the most likely problem is the Fuser unit. This is a part that plays an important role in the printing process. This unit melts the toner and compresses it in order to leave the impression on the paper with heat. A faulty fuser unit will not compress correctly and leave wet ink on the paper causing it to smear.
Answer:
The Function is given as
=IF(AND(E8="No",G8>10),"Need to remodel","No Change")
Explanation:
The syntax of the IF condition in excel is given as
IF(Test,If true,If false)
So here the test is an and component such that the house has to be unoccupied which is indicated as E8 because the E column contain the occupancy of the apartments, and the G8 is the last remodeling time, so the test statement is the AND operation of the conditions as
E8="No" indicating that house is unoccupied
G8>10 indicating that the last remodelling was more that 10 years ago
So the test is given as
AND(E8="No",G8>10)
Now the statement if the test true is the recommendation for to remodel, so
"Need to remodel"
Now the statement if the test is false is given as
"No Change"
So the overall function becomes
=IF(AND(E8="No",G8>10),"Need to remodel","No Change")
#include <iostream>
#include <vector>
std::vector<int> v;
int main(int argc, char* argv[]) {
while(1) {
int temp;
std::cout << "\nEnter a number: ";std::cin>>temp;
if(temp<0) {
std::cout << "\nEven number(s) is/are:\n---------------------\n";
for(int i=0;i<v.size();i++) {
if(v.at(i)%2==0) std::cout << v[i] << " ";
else continue;
}
std::cout << std::endl;
break;
}else {
v.push_back(temp);
}
}
return 0;
}
Answer:
The answer is "Option A"
Explanation:
In the OOPs programming language, the class and object concept is used, in which class is a collection of data members, and member function and object is known as real-time entity. In the class when the main method is created, so inside this method class object is created that's why the answer to this question is true.
