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2 years ago

What are the solutions of x^2 + 10x+16=0

Mathematics

2 answers:

svp [43]2 years ago

6 0

x^2+8x+2x+16=0

or,x(x+8)+2(x+8)=0

or,(x+2)(x+8)=0

therefore,

x=-2,-8

Digiron [165]2 years ago

5 0

Answer:

x=−2,−8

Step-by-step explanation:

Move terms to the left side. Then set each factor equal to zero.

x=−2,−8

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This can be calculated using the formula:
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3 years ago

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Answer:

≈ 8.07 mg

Step-by-step explanation:

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2 years ago

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nadya68 [22]

Answer:

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Step-by-step explanation:

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2 years ago

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=====================================

Work Shown:

$y = 192\left(4^{x-3}\right)\\\\196,608 = 192\left(4^{x-3}\right)\\\\\frac{196,608}{192} = 4^{x-3}\\\\1024 = 4^{x-3}\\\\4^{x-3} = 1024\\\\\log\left(4^{x-3}\right)=\log\left(1024\right)\\\\(x-3)*\log\left(4\right)=\log\left(1024\right)\\\\x-3=\frac{\log\left(1024\right)}{\log\left(4\right)}\\\\x-3=5\\\\x=5+3\\\\x=8\\\\$

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2 years ago

Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who

zmey [24]

Answer:

18.7939 m

Step-by-step explanation:

-Let x be the distance between John and clock tower.

-Let y be the vertical distance from the eyes of the two men standing to the top of the clock tower.

#Taking the right triangle ACD:

$\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5$

#Taking the right triangle ABD:

$\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5$

#We equate the two yo solve for x and y;

$(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939$

Hence, John's distance from the tower's base is 18.7939 m

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2 years ago