Question

A wire carrying a 25.0 A current bends through a right angle. Consider two 2.00 mm segments of wire, each 3.00 cm from the bend (Figure 1).
a) Find the magnitude of the magnetic field these two segments produce at point P , which is midway between them.
b) Find the direction of the magnetic field at point P

Answer 1

The magnitude of the magnetic field and the direction of the magnetic field at point P is mathematically given as

B=1.9*10^{-5}T

To determine the magnetic field direction, use the right-hand -rule on the page magnetic field is going.

What is the magnitude of the magnetic field these two segments produce at point P, which is midway between them.?

Generally, the equation for Biot savant law is  mathematically given as

$B=(\frac{u}{4\pi}*{\frac{Ilsin\theta}{r^2})$

Their net field is

Bn=2B

$Bn=2* B=(\frac{u}{4\pi}*{\frac{Ilsin\theta}{r^2})$

Hence

$B=(\frac{4*\p *10^{-7}}{4\pi}*{\frac{(30)(2*10^{-3}sin45)}{\sqrt{(3*10^{-2})^2+((3*10^{-2})^2)}/2})$

B=1.9*10^{-5}T

In conclusion, To determine the magnetic field direction, use the right-hand -rule on the page magnetic field is going.

Read more about the magnetic field

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