Answer:
y = 2/3x + 4
Step-by-step explanation:
Slope-intercept form of a line:
- y = mx + b
- where m = slope and b = y-intercept
To find the equation of a line, we need two points that the line passes through.
We can use the x-intercept and y-intercept of the line: (-6,0) and (0,4), respectively.
Find the slope of the line using these two points:
- Slope formula:
Plug the two points into the formula.
Subtract and simplify this fraction.
The slope of this line is m = 2/3.
Now we can look at the graph to determine the y-intercept of this line; the line intersects the y-axis at (0,4) so the constant b = 4.
We can use the slope, m, and the y-intercept, b, and substitute these values into the slope-intercept form of a line.
The equation of the line is y = 2/3x + 4.
Answer:
x = 6
Step-by-step explanation:
-(x - 8) = 2
multiply the negative
-x + 8 = 2
subtract 8 from both sides
-x = -6
x = 6
The open circle means the inequality will be greater than or equal to (≥) or less than or equal to (≤).
A closed circle means the inequality will be greater than (>) or less than (<)
An arrow pointing right to increasingly positive values means the inequality is getting greater (> or ≥)
A narrowing pointing left to increasingly negative values means the inequality is getting lesser (< or ≤)
So for this graph with an open circle and rightward pointing arrow, “x” will be some number on the number line greater than the first point of -38:
x > -38
9514 1404 393
Answer:
- |w -30| > 1.6
- (-∞, 28.4) U (31.6, ∞)
Step-by-step explanation:
1. The snack bags will be rejected if their weight differs from 30 grams by more than 1.6 grams:
|w -30| > 1.6
__
2. This inequality resolves to two inequalities.
w -30 > 1.6
w > 31.6 . . . . . add 30
and
-(w -30) > 1.6
w -30 < -1.6 . . . multiply by -1
w < 28.4 . . . . . add 30
The solution in interval notation is the union of the two disjoint intervals:
(-∞, 28.4) U (31.6, ∞)
You have to remember when you divide the sign flips and it doesn’t change to let’s say greater than or equal to it just changes to the opposite side