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koban [17]
4 years ago
13

Describing a Physical Change

Mathematics
2 answers:
andreev551 [17]4 years ago
5 0
A physical change is a type of change in which the form of matter is altered but one substance is not transformed into another. For example, crumbling up a piece of paper. It’s still a piece of paper and you uncrumble it and it is still paper.
Eduardwww [97]4 years ago
5 0

Answer:

During Physical Change there would be a re-arrangements of atoms or molecules, changes of the arrangement may be change in the distance between atoms or molecules, change in the crystal form, .....etc

for example: water when heated it undergoes a Physical Change and turn into vapor, this means the heat cause the distance between water molecules to increase, so it transferred from the liquid form to the gas form.

NOTE that in Physical Change there is no change in the chemical structure and the material retains all its chemical properties, and no new compounds are produced.

again, A physical change is any change not involving a change in the substance's chemical identity. Matter undergoes chemical change when the composition of the substances changes: one or more substances combine or break up (as in a relationship) to form new substances.Physical changes occur when objects undergo a change that does not change their chemical nature. A physical change involves a change in physical properties. Physical properties can be observed without changing the type of matter. Examples of physical properties include: texture, shape, size, color, odor, volume, mass, weight, and density.

BUT in Chemical Change ( or Chemical Reaction ) there would be change in the chemical nature of the material undergoing a Chemical Change with the production of new compounds.

MARK ME BRAINIEST

Step-by-step explanation:

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The weights of the fish in a certain lake are normally distributed with a mean of 11 lb and a standard deviation of 6. if 4 fish
Alexus [3.1K]

Since the sample standard deviation is now known, we use the z-score test. The formula is given as:

z= (X – μ) / (s / sqrt(n))

Where,

X = sample mean = 8.6 lb to 14.6 lb

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s = population standard deviation = 6

n = sample size = 4

1st: Calculating for z when x = 8.6 lb

z = (8.6 – 11) / (6 / sqrt4)

z = - 0.8

Using the standard distribution table for z:

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2nd: Calculating for z when x = 14.6 lb

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Using the standard distribution table for z:

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Therefore the probability that the mean weight will be between 8.6 and 14.6 lb:

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