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Sergeeva-Olga [200]
2 years ago
11

What is the simplified form of the expression the quantity x squared minus 4x minus 21 end quantity divided by 4 times the quant

ity x plus 3 end quantity?
Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0

The simplified form of the given expression \frac{x^2-4x-21}{4(x+3)} is \frac{x-7}{4}.

<h3>How to simplify a fractional expression?</h3>

The steps to simplify a fractional expression are:

  • Factorize the expressions both in the numerator and the denominator using different methods
  • Remove the common terms in the numerator and denominator
  • Thus, the simplified expression will be obtained.

<h3>Calculation:</h3>

The given expression is \frac{x^2-4x-21}{4(x+3)}

Factorizing the numerator:

x² - 4x - 21 = x² - 7x + 3x - 21

                 = x(x - 7) + 3(x - 7)

                 = (x - 7)(x + 3)

Then,

\frac{x^2-4x-21}{4(x+3)} = \frac{(x-7)(x+3)}{4(x+3)}

common factor (x + 3) is canceled out from both the numerator and the denominator

So,

\frac{x^2-4x-21}{4(x+3)} = \frac{x-7}{4}

Therefore, the simplified expression is \frac{x-7}{4}.

Learn more about simplifying an expression here:

brainly.com/question/13742517

#SPJ1

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