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yaroslaw [1]
3 years ago
8

Find the solution of this system of equations:

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

y=-3.667

x=

Step-by-step explanation:

-4(10y-59)+10y=86

30y+196=86

30y=-110

y=-3.667

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Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has
MrMuchimi

The answer to this question is C

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2 years ago
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Suppose y = 2x + 1 , where x and y are functions of t. (a) if dx/dt = 3, find dy/dt when x = 4. dy dt = (b) if dy/dt = 2, find d
qwelly [4]

Answer:

Step-by-step explanation:

If y = 2x + 1, then dy/dt = 2(dx/dt).

If y = 2x + 1, then y = 2(40) + 1 when 40 is substituted for x.  y = 81.

(a) if dx/dt = 3, find dy/dt when x = 4:

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(b) if dy/dt = 2, find dx/dt when x = 40:

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3 0
2 years ago
Round to the nearest cent 2.303?
aksik [14]
2.3

Hope this helped!
5 0
3 years ago
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If the angle bisectors of a pair of opposite angles of a quadrilateral are the opposite sides of a parallelogram formed by the t
Novosadov [1.4K]

Answer:

The correct answer is;

No, the quadrilateral is not always a parallelogram

Step-by-step explanation:

Since there are only four opposite angles in a quadrilateral there are only two possible angle bisectors of the opposite angles also, the angle bisectors of a pair of opposite angles of a quadrilateral will intersect within the quadrilateral and therefore they cannot form the sides of a parallelogram

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3 years ago
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