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Ainat [17]
3 years ago
6

Evaluate 4x²-12x when x=(3/2)-(i/2).

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

-10

Step-by-step explanation:

Let´s evaluate the complex number:

4*(\frac{3}{2} -\frac{1}{2}i)^{2} -12*(\frac{3}{2} -\frac{1}{2}i)

First let's calculate this expression:

(\frac{3}{2} -\frac{1}{2}i)^{2} =(\frac{3}{2} -\frac{1}{2}i)*(\frac{3}{2} -\frac{1}{2}i)

Using distributive property:

(\frac{3}{2} )^{2} -2*(\frac{3}{2}*\frac{1}{2}i )+(\frac{1}{2}i )^{2}

Where:

i=\sqrt{-1}

Therefore:

2-\frac{3}{2} i

Evaluating the rest of the expression using the distributive property again:

4*(2-\frac{3}{2} i)-12*(\frac{3}{2} -\frac{1}{2}i)=8-6i-18+6i=-10

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• So we know that.....

x represent bags of snack and y is bottles of water.


This equations shows the total amount and the cost of each water bottle and snack:

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Total: $20.00
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And this question shows the total items:

11 = x + y

Which there will be some snack + some water bottle = 11 items


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• Now I’m going to first solve for x, which is the amount of bags of snack.

I will use the equation, 11 = x + y.

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11 - y = x —> so x is equal to 11 minus y.


—————————————————————

• Now we’re going to plug the 11 - y as x in the equation: 20.00 = 2.50x + 1.00y to solve for y.

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ANSWER:

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Answer:

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Step-by-step explanation:

This is a permutation, not a combination, because order matters.

Here's why:

Arbitrarily, let's say that the three students chosen for the award are Abby, Bob, and Charlie. The order of which each award is given to the three of them matters, because otherwise they would be receiving different awards. For example, if Abby gets the research award, Bob gets the teaching award, and Charlie gets the service award, this would be notably different than if Abby got the teaching award, Bob got the service award, and Charlie got the research award.

Therefore, for the first award, we have 25 people to choose from. After we select that person, we have 24 people to choose from, since the problem stipulates that each student can receive at most one award. Then 23, and so on.

Since we're choosing three people to give awards to, there are:

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